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Dima020 [189]
3 years ago
11

Suppose f(x) is continuous on [2,8] and −4≤f′(x)≤5 for all x in (2,8). Use the Mean Value Theorem to estimate f(8)−f(2).

Mathematics
1 answer:
bazaltina [42]3 years ago
6 0
<span>2≤x≤8</span> <span>−4≤<span>f′</span>(x)≤5</span> f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that <span><span>f′</span>(c)=<span><span>f(8)−f(2)</span><span>/8−2</span></span></span> And we know <span>−4≤<span>f′</span>(c)≤5</span> => we have <span>−4≤ <span><span>f(8)−f(2)</span><span>/8−2</span></span> ≤<span>5</span></span>
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3 years ago
Given that f(x)=x2-1 and g(x)=2x+8 find (g-f)(10)
irga5000 [103]

Answer:

<h2>(g-f)(10) = - 71</h2>

Step-by-step explanation:

f(x) = x² - 1

g(x) = 2x + 8

To find (g-f)(10) first find ( g - f)(x)

To find ( g - f)(x) subtract f(x) from g(x)

That's

( g - f)(x) = 2x + 8 - ( x² - 1)

Remove the bracket

( g - f)(x) = 2x + 8 - x² + 1

Simplify

( g - f)(x) = - x² + 2x + 9

To find (g-f)(10) substitute the value in the bracket that's 10 into ( g - f)(x)

That is

(g-f)(10) = -(10)² + 2(10) + 9

= - 100 + 20 + 9

= - 100 + 29

= - 71

Hope this helps you

7 0
3 years ago
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Anon25 [30]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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34kurt

Answer:

If a = 5 and b = 3, then that means 2a - 3b + 3a = 16

Step-by-step explanation:

2a - 3b + 3a

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