Answer:
The width of the area model is equal to
Step-by-step explanation:
<u><em>The complete question is</em></u>
Todor was trying to factor 10x^2-5x+15 he found the greatest common factor of these terms was 5 what is the width
we know that
The area of a rectangular model is given by the formula
----> equation A
where
L is the length
W is the width
we have
Factor the expression
substitute the value of the Area in the equation A
In this problem
The greatest common factor of these terms is the length (L=5 units)
so
we can say that the width is equal to (2x^2-x+3)
therefore
The width of the area model is equal to
Answer:
x^8 * y^3
Step-by-step explanation:
Square both sides to get (x^10 * y^4)/(x^2 * y). Divide both sides by x^2 to get (x^8 * y^4)/y. Divide both sides by y to get x^8 * y^3.
Approximately Bell- shaped
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One is 60, the other is 120. Imagine 3x equals 180. 60 is x, and 2x, or the bigger angle is 120.
Answer:
x = 13
Step-by-step explanation:
m∠ABC + m∠CBD = 180° {linear pair}
3x + 43 + 6x + 20 = 180
3x + 6x + 43 + 20 = 180
9x + 63 = 180
9x = 180 - 63
9x = 117
x = 117/9
x = 13