Olate the variable by dividing each side by factors that don't contain the variable.
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-5 ≤ 3m + 1 < 4
- 1 - 1 - 1
-6 ≤ 3m < 3
3 3 3
-2 ≤ m < 1
Solution Set: {m|-2 ≤ m < 1}, {m|m ≥ -2 and m < 1}, [-2, 1)
The answer is A.
Answer:
Step-by-step explanation:
From the information given,
Mark: 6,7,8,9,10
frequency:5,4,7,10,4
a) Range = highest mark - lowest mark
Range = 10 - 6 = 4
b) The number of students in the group is the sum of the frequency. Therefore,
Number of students = 5 + 4 + 7 + 10 + 4 = 30 students
c) Mean mark = (mark × frequency)/total frequency
[(6 × 5) + (7 × 4) + (8 × 7) + (9 × 10) + 10 × 4)]/ 30
Mean mark = (30 + 28 + 56 + 90 + 40)/30 = 244/30
Mean mark = 8.1
Answer:
1. a. 3xy²(7x²y³ + 5x - 4y)
2. a. (3x + 2)(5x + y)
3. d. (2a + b)(5x - 4)
Step-by-step explanation:
For #1, your answer was missing an exponent, which I boldfaced. Every term has a <em>y</em><em>²</em><em> </em>in common. Then, in numbers 2 and 3, just factor each group one at a time.
Ex: [10ax + 5bx] - [8ay - 4by]
The slope of a graph is rise over run. So count how many units up you move and put that over how many units right you move. If you are moving down or to the left it would be negative.
