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3 years ago

What's the area of the trapezoid?

Mathematics

2 answers:

omeli [17]3 years ago

5 0

Answer:

51.2

Step-by-step explanation:

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Lelechka [254]3 years ago

3 0

Answer:

Mark brainliest please if i am correct one more brainliest please

Step-by-step explanation:

A=a+b

2h=15+25

2·5=100

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Tom observed how many times his dog jumped whenever he met a new person. Use the data set below to determine the interquartile r

Ad libitum [116K]

Hey Astraled, your answer is D)3

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3 0

3 years ago

PLEASE HELP find value of x and y

bazaltina [42]

Given : 

There is a quadrilateral.
Two sides of the quadrilateral are parallel .
Four angles are 96° , 2x° , 94° & ( 3y + 44 )°.

To Find :-

The value of x & y .

Solution :-

Here , 96° & 2x° are co - interior angles and we know that the sum of co - Interior angles is 180°.

⇒ 96° + 2x = 180° .

⇒ 2x = 180° - 96° .

⇒ 2x = 84° .

⇒ x = $\red{\sf \dfrac{84^{\circ}}{2}}$

$\bf\longmapsto x = 42^{\circ}$

Hence value of x is 42° .

Similarly , 94° & ( 3y + 44) ° are co- interior angles

⇒ 94° + ( 3y + 44)° = 180° .

⇒ ( 3y + 44 )° = 180° - 94° .

⇒ 3y + 44° = 86°.

⇒ 3y = 86° - 44° .

⇒ 3y = 42° .

⇒ y = $\sf \red{\dfrac{42^{\circ}}{3}}$

$\bf\longmapsto y = 14^{\circ}$

Hence the value of y is 14°.

8 0

3 years ago

An investor buys $15,000 worth of stocks. The price of one kind of stock is $35 per share, and the price of the other kind of st

liq [111]

Answer:

300

Step-by-step explanation:

6 0

3 years ago

What is the equation of the quadratic graph with a focus of (4,3) and a directrix of y=-6

Rufina [12.5K]

Answer:

f(x) = (1/18)x^2 - (4/9)x - 65/18

Step-by-step explanation:

Since the focus (4,3) is higher up than is the directrix y = -6, the vertex is between y = -6 and y = 3, halfway between these values, to be exact: y = -3/2. Thus, the y-coordinate of the vertex is (-6 + 3/2), or -4.5. The x-coordinate of the vertex is 4, which comes from that 4 in (4,3). Thus, the vertex is (4, -4.5) or (4, -4 1/2).

The standard equation for a vertical parabola with vertex at (h,k) is:

4p(y-k) = (x-h)^2, where p is the distance between vertex and focus or between vertex and directrix. In this case p = 4.5. Thus, the equation of this quadratic is 4(4.5)(y - [-4.5]) = (x - 4)^2, or

18(y+4.5) = (x-4)^2, or y+4.5 = (1/18)(x-4)^2.

Let's expand this and rewrite the result as a quadratic equation in standard form y = ax^2 + bx + c:

y + 4.5 = (1/18)(x^2 - 8x + 16). Multiplying all terms by 18 to remove both fractions, we get:

18y + 81 = x^2 - 8x + 16. Rearranging these terms, we get:

18y = x^2 - 8x + 16 - 81, or

18y = x^2 - 8x - 65, or

y = f(x) = (1/18)x^2 - (4/9)x - 65/18.

5 0

3 years ago

Read 2 more answers

A Rectangular has area 12a^2 and perimeter 14a what are the dimensions of this Rectangular?

Nataliya [291]

9514 1404 393

Answer:

3a by 4a

Step-by-step explanation:

For dimensions L and W, the area and perimeter are ...

A = LW = 12a^2

P = 2(L+W) = 14a

Using the second equation, we can find L:

L +W = 7a . . . . . divide by 2

L = 7a -W

Substituting into the area formula gives the quadratic ...

(7a -W)(W) = 12a^2

W^2 -7aW +12a^2 = 0 . . . . arrange in standard form

(W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)

Then we have the two solutions ...

W = 3a, L = 4a

W = 4a, L = 3a

The rectangle dimensions are 3a by 4a.

5 0

2 years ago