Question

the length of the rectangle shown above is (x+9). the width of the rectangle is (2x+3). Find the area of the rectangle.

Answer 1

(x+9)(2x+3)=2x^2+3x+18x+27=2x^2+21x+27

Answer 2

Answer: Area of rectangle =2x² + 21x + 27

Step-by-step explanation:

Given :

Length of the rectangle = x + 9

Width of the rectangle = 2x + 3

We have to find area of the rectangle ?

Area of rectangle = Length × Breadth

Area of the rectangle = $(x +9) \times (2x+3)$

Area = $x \times (2x+3) + 9 \times ( 2x+3)$

Area =2$x^{2}$ + $3\times x$ + $9\times 2x$ + $9\times 3$

Area =$2x^{2}$ + $3x$ + $18x$ + $27$

Area =$2x^{2} + 21x + 27$

∴ Area of  rectangle = $2x^{2} +21x+ 27$