First, you'd have to turn the fraction into a decimal.You would divide the numerator by the denominator. 7/8=0.875
Now, you turn the decimal to a percent.
You move the decimal point two places to the right.
087.5
87.5% would be your answer.
Answer:
98.01% probability of getting 5 clean sheets
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, the order that the sheets are chosen is not important, so we use the combinations formula to solve this problem.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

0.4% of the sheets contain spots
Of 500, that is 0.004*500 = 2.
What is the probability of getting 5 clean sheets although 0.4% of the sheets contain spots?
Desired outcomes
2 are defective, so 5 sheets from a set of 500 - 2 = 498.

Total outcomes
5 sheets from a set of 500.

Probability:

98.01% probability of getting 5 clean sheets
Y=x^2+10x+11
y=x^2+x-7
therefore,
x^2+10x+11=x^2+x-7
x^+10x+11-x^2-x+7=0
9x+18=0
x=-2
y=(-2)^2+10(-2)+11= -5
<h3>
Answer: sometimes true</h3>
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Explanation:
The plane P can be thought of a perfectly flat ground. Now imagine a flag pole which represents line GH. If AB is drawn in chalk on the pavement, and this line AB intersects the base of the flagpole, then we've made AB and GH intersect. However, this example shows that GH is <u>not</u> on the plane P.
Is it possible to have GH be in the the plane? Yes. We could easily draw another chalk line on the ground to have it intersect AB somewhere. But as the previous paragraph says, it's also possible that GH is not in the plane.
Therefore, the statement is sometimes true