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Elan Coil [88]
3 years ago
15

Triangle XYZ is rotated 90° counterclockwise using the origin as the center of rotation.

Mathematics
2 answers:
lina2011 [118]3 years ago
8 0

Answer:

im pretty sure its 270 clockwise.

Step-by-step explanation:

Mnenie [13.5K]3 years ago
5 0

B) 270 degrees clockwise

I just took the quiz on edge

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Try this, please!
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Check the picture below.

the triangle is an isosceles, so it has twin legs, and a base bottom.

the twin sides stem from the "vertex", and we know the vertex is 120°, and since the triangle is inscribed in a circle, because the circle is "circumscribing" it, then the base side of the triangle will be the diameter of it.

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Liono4ka [1.6K]

Answer:

Q7. 11.3 inches (3 s.f.)

Q8. 96.2 ft

Q9. 36.4cm

Step-by-step explanation:

Q7. Please see attached picture for full solution.

Q8. Let the length of a side of the square be x ft.

Applying Pythagoras' Theorem,

34^{2}  =  {x}^{2}  +  {x}^{2}  \\ 2 {x}^{2}  = 1156 \\  {x}^{2}  = 1156 \div 2 \\  {x}^{2}  = 578 \\ x =  \sqrt{578}  \\

Thus, the perimeter of the square is

= 4( \sqrt{578} ) \\  = 96.2 ft\:  \:  \: (3 \: s.f.)

Q9. Equilateral triangles have 3 equal sides and each interior angle is 60°.

Since the perimeter of the equilateral triangle is 126cm,

length of each side= 126÷3 = 42 cm

The green line drawn in picture 3 is the altitude of the triangle.

Let the altitude of the triangle be x cm.

sin 60°= \frac{x}{42}

\frac{ \sqrt{3} }{2}  =  \frac{x}{42}  \\ x =  \frac{ \sqrt{3} }{2}  \times 42 \\ x = 21 \sqrt{3}  \\ x = 36.4

(to 3 s.f.)

Therefore, the length of the altitude of the triangle is 36.4cm.

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Answer is A: when you add all the percents it’s 50 the rest is 50%
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