The answer to this question is line 1
Answer:
10
Σ [n^2]
i=1
Step-by-step explanation:
Hope I helped? I inserted it into a calc and I also got 385 for something if its useful))
1) What is the slant height x of this square pyramid? Express your answer in radical form
sin 60=x/4--------> x=4*sin 60------> 4*(√3/2)-------> 2 √3 m
the answer Part 1) is 2 √3 m
2) The base of a regular pyramid is a hexagon. What is the area of the base of the pyramid?
[area of the base}=[area of hexagon]
[area of hexagon]=6*[area of triangle]
area of triangle
sin 60=a/14-------> a=(√3/2)*14-------> a=7√3 cm
cos 60=(b/2)/14--------> (b/2)=cos 60*14-----> (1/2)*14---------> (b/2)=7
base of triangle=2*7--------> b=14 cm
[area of triangle]=14*7√3 /2--------> 49√3 cm²
so
[area of hexagon]=6*[49√3]--------> 294√3 cm²
Answer: 214 sq ft
Step-by-step explanation:
A=2(wl+hl+hw)=2·(6·5+7·5+7·6)=214
