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4 years ago

A set of equations is given below:

Mathematics

1 answer:

Elza [17]4 years ago

4 0

y=2x+6

y=2x+2

Solve y=2x+6 for y

Substitute 2x+6 for y in y=2x+2

y=2x+2

2x+6=2x+2

Add -2x to both sides

2x+6-2x= 2x+2-2x

6=2

Add -6 to both sides

6-6=2-6

0=-4

No Solution

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Expand & simplify<br> (x— 6)(x + 6)<br> ©

aleksley [76]

Answer:

X - 6 = X + 6

Step-by-step explanation:

6 0

3 years ago

The functionâ€‹ s(t) represents the position of an object at time t moving along a line. Suppose s (3 )equals 156 and s (6 )equa

bixtya [17]

Answer: The average velocity of the object over the time interval [3,6] is 20.

Step-by-step explanation:

Since we have given that

s(3) = 156

s(6) = 216

We need to find the average velocity over the time interval [3,6].

So, average velocity becomes

$\dfrac{s(t_1)-s(t_0)}{t_1-t_0}\\\\=\dfrac{s(6)-s(3)}{6-3}\\\\=\dfrac{216-156}{3}\\\\=\dfrac{60}{3}\\\\=20$

Hence, the average velocity of the object over the time interval [3,6] is 20.

5 0

3 years ago

Which expressions are equivalent to -6+4q+(-6q)

nlexa [21]

Answer:

-2 (q + 3)

Step-by-step explanation:

Simplify the following:

-6 + 4 q - 6 q

Grouping like terms, -6 + 4 q - 6 q = (4 q - 6 q) - 6:

(4 q - 6 q) - 6

4 q - 6 q = -2 q:

-2 q - 6

Factor -2 out of -2 q - 6:

Answer: -2 (q + 3)

3 0

4 years ago

Read 2 more answers

Need help, I cant simplify this

Kisachek [45]

Answer:

$7^{\frac{2}{5}}$

Step-by-step explanation:

Step 1: First apply radical rule in the given expression.

$\sqrt[n]{a}=a^{\frac{1}{n}}$

Here, $\sqrt[3]{7}=7^{\frac{1}{3}}, \sqrt[5]{7}=7^{\frac{1}{5}}$

The expression becomes $\frac{\sqrt[3]{7}}{\sqrt[5]{7}}=\frac{7^{\frac{1}{3}}}{7^{\frac{1}{5}}}$

Step 2: Now, apply exponent rule in the above expression

$\frac{x^{m}}{x^{n}}=x^{m-n}$

So, the expression becomes, $7^{\left(\frac{1}{3}-\frac{1}{5}\right)}$ .

Step 3: Take cross multiply the denominator and numerator of the fraction in the power of 7.

$\Rightarrow 7^{\left(\frac{1}{3}-\frac{1}{5}\right)}=7^{\left(\frac{5-3}{15}\right)}=7^{\frac{2}{5}}$

The answer is $7^{\frac{2}{5}}$ .

Hence the simplified form of $\frac{\sqrt[3]{7}}{\sqrt[5]{7}}=7^{\frac{2}{5}}$ .

3 0

3 years ago

Lo opuesto de lo opuesto de 4

Shtirlitz [24]

La respuesta es -4 porque es antes del 0

5 0

4 years ago