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3 years ago

10

The functionâ€‹ s(t) represents the position of an object at time t moving along a line. Suppose s (3 )equals 156 and s (6 )equa

ls 216. Find the average velocity of the object over the interval of time [3 comma 6 ].

1 answer:

bixtya [17]3 years ago

5 0

Answer: The average velocity of the object over the time interval [3,6] is 20.

Step-by-step explanation:

Since we have given that

s(3) = 156

s(6) = 216

We need to find the average velocity over the time interval [3,6].

So, average velocity becomes

$\dfrac{s(t_1)-s(t_0)}{t_1-t_0}\\\\=\dfrac{s(6)-s(3)}{6-3}\\\\=\dfrac{216-156}{3}\\\\=\dfrac{60}{3}\\\\=20$

Hence, the average velocity of the object over the time interval [3,6] is 20.

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3 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

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Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

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The sum of first six terms.

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Sum of first n terms of a GP is

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Putting n=2, we get

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$S_4=\dfrac{a(1-r^4)}{1-r}$

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Taking square root on both sides, we get

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Case 2: If r is negative, then using (ii) we get

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The sum of first 6 terms is

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$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

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