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Alex_Xolod [135]
3 years ago
13

Simplify sin q + cosq cotq.

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0
\sin q+\cos q\cot q=\sin q+\cos q\cdot\dfrac{\cos q}{\sin q}=\sin q+\dfrac{\cos^2q}{\sin q}\\\\=\dfrac{sin^2q}{\sin q}+\dfrac{\cos^2q}{\sin q}=\dfrac{\sin^2q+\cos^2q}{\sin q}=\dfrac{1}{\sin q}=\csc q\\\\Used:\\\cot q=\dfrac{\cos q}{\sin q}\\\\\sin^2q+\cos^2q=1\\\\\csc q=\dfrac{1}{\sin q}
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Ann and ben had some apples. The ratio of the number of Ann's apples to the ratio of Ben's apple is 2:3. Ann gave 6 apples to be
aleksklad [387]

Answer:

There are 12 apples in total.

Step-by-step explanation:

If Anne gave Ben 6 apples then heres how:

2:3 subrtact 6 apples = 1:3

6 apples x 2 = 12 apples =

2 ÷ 2 = 1

Hence, your answer is double 6 which is 12 apples.

Hope this helps :)

3 0
3 years ago
Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. A samp
shutvik [7]

Answer:

0.9910 = 99.10% probability that a sample of 170 steady smokers spend between $19 and $21

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20, standard deviation of 5:

This means that \mu = 20, \sigma = 5

Sample of 170:

This means that n = 170, s = \frac{5}{\sqrt{170}}

What is the probability that a sample of 170 steady smokers spend between $19 and $21?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{\frac{5}{\sqrt{170}}}

Z = 2.61

Z = 2.61 has a p-value of 0.9955

X = 19

Z = \frac{X - \mu}{s}

Z = \frac{19 - 20}{\frac{5}{\sqrt{170}}}

Z = -2.61

Z = -2.61 has a p-value of 0.0045

0.9955 - 0.0045 = 0.9910

0.9910 = 99.10% probability that a sample of 170 steady smokers spend between $19 and $21

3 0
3 years ago
Julain has 200ml of 35% hand sanatizer. Sarah has 150ml of 85% hand sanatizer. They mix the sanatizers together in an effort to
Cerrena [4.2K]

Answer:210ml, 140 ml, 60%

Step-by-step explanation:

Given

Juli has 200 ml of 35% hand sanitizer

Sarah has 150 ml of 85% hand sanitizer

The mixture has 60% con. i.e. 60 % is Alcohol and 40 % water

The final volume of the mixture =200+150=350 ml

Now, 60% of 350 ml= 350\times 0.6=210\ ml

So, pure Alcohol is 210 ml

Water in the final mixture= 350\times 0.4=140\ ml

The concentration of Alcohol is 60%

7 0
3 years ago
Write the correct answer:
natta225 [31]

Answer:

-1 for question 1, -11 for question 2, 7 for question 3

Step-by-step explanation:

8 0
3 years ago
Round 9 2/4 to the nears whole number
Ipatiy [6.2K]
9 and 2/4 can be written as 9.5 in decimals. We usually round 5 up, so we would round it to 10.

if it was 9.4 we would round it down to 9.
6 0
3 years ago
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