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Roman55 [17]
3 years ago
13

Solutions pls I need help….

Mathematics
1 answer:
Sati [7]3 years ago
6 0

Answer:

9

Step-by-step explanation:

Setup a proportion

\frac{40}{60} = \frac{6}{n}

Cross multiply

40n = 360

Divide by 40

40n/40 = 360/40

n = 9

You might be interested in
. A tennis supply store pays a wholesaler $90 for a tennis racquet and sells it for $144. What is the markup rate?
I am Lyosha [343]


Formula : Amount of change / Original amount

             1.      144 - 90/ 144

             2.      Subtract 144 and 90

             3.      54/ 144

             4.      Divide 54 by 144

             5       0.375

             6       Move the decimal two places to the right.

              7.      37.5 %

Answer: 37.5% is the markup rate

6 0
3 years ago
ANSWER THIS TO GET 23 POINTS AND BRAINLIEST
puteri [66]

<em>Ohhh, interest problems. I haven't done an equation like this in a long time, but I will attempt.</em>

<em>I would say that the answer is the 2nd option. The equation is i = (5200)(0.06)(2.5).</em>

<em>The traditional interest formula is I = (P)(R)(N).</em>

<em>P = the original amount of money given</em>

<em>R = interest rate</em>

<em>N = the amount of time</em>

<em />

<em>I hope this answers your question (and that I understood the question correctly!).</em>

<em>-Toremi</em>

6 0
3 years ago
4)
Gnesinka [82]

Answer:

a is 25 b is 15 percent

Step-by-step explanation:

8 0
3 years ago
The data below gives the number of speeding tickets given per day at a certain location on a highway over a two-week period.
kramer
Do you have the rest of the answers ? 

6 0
3 years ago
The manager of a restaurant found that the cost to produce 150 cups of coffee is ​$ 20.00​, while the cost to produce 400 cups i
34kurt

Answer: Our required linear equation would be 10y-x=50

Step-by-step explanation:

Since we have given that

Number of cups = 150

Cost = $20

Number of cups = 400

Cost = $45

Let x be the number of cups, y be the cost .

We will use "Equation of line using Two point slope":

y-20=\dfrac{45-20}{400-150}(x-150)\\\\y-20=\dfrac{25}{250}(x-150)\\\\10(y-20)=(x-150)\\\\10y-200=x-150\\\\10y-x=-150+200\\\\10y-x=50

Hence, our required linear equation would be 10y-x=50

4 0
3 years ago
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