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sveta [45]
3 years ago
14

NEED HELP PLZ The following table shows the number of hours some students in two neighborhoods spend walking to school each wee

k: Neighborhood A 5 2 4 2 5 5 4 5 2 Neighborhood B 4 5 5 1 12 2 2 1 3 Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (6 points) Part B: Are the box plots symmetric? Justify your answer. (4 points)

Mathematics
1 answer:
Leni [432]3 years ago
5 0
Firstly, order the two data set from smallest to largest as shown in diagram below

The value of median, Q2 is the 5th value of both set
The value of Q1 and Q3 is the first and third quarter of the set
The range of data set one is 5-2=3 and of set two is 12-1=11
The interquartile range of set one is 5 - 2 = 3
The interquartile range of set two is 5 - 1.5 = 3.5

The box plot is not symmetrical for either data set

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How does the length of the hypotenuse in a right triangle compare to the lengths of the legs?
gavmur [86]

we know that

In a right triangle we have

two legs and one hypotenuse

Let

a,b -----> the legs of the right triangle

c-----> the hypotenuse of the right triangle (the greater side)

Applying the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

therefore

<u>the answer is</u>

The length of the hypotenuse squared is the length of one leg squared plus the length of another leg squared

6 0
4 years ago
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There are 11 people in a room. Are there any outliers in the room? If
Katarina [22]

Answer:

D

Step-by-step explanation:

1, 17, and 20 are very different from the average numbers in this list.

6 0
3 years ago
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How much material is needed to construct a triangular tent that is 6 feet wide 4 feet tall and 8 feet long with side measurement
jonny [76]

Answer: 152ft^2

The amount of material needed to construct the tent is 152ft^2

Step-by-step explanation:

The amount of material needed to construct a triangular tent= the surface area of the triangular tent.

S.A = area of the 2 side rectangles + area of the 2 side triangles + area of the base.

S.A = Ab + At + Ar ....1

Area of the base Ab= Length × width = 8×6 = 48ft^2

Area of the two triangles At = 2 × 0.5 × width × height

At = width × height = 6×4 = 24ft^2

Area of the two rectangles Ar = 2 × side measurement × length

Side measurement is given as 5ft.

or it can be calculated using;

Side length can be calculated using Pythagoras theorem.

Examining the figure attached, we can see that;

Side breadth b = √(h^2 + (w/2)^2)

b = √(4^2 + (6/2)^2) = √(16+9) = √25

b = 5ft

Ar = 2×5×8 = 80ft^2

From eqn1, S.A can be solved as;

S.A = 48 + 24 + 80

S.A = 152ft^2

7 0
4 years ago
I need help. You can have brainliest. Plz <br> Thanks
Katena32 [7]

Answer:

B:

Step-by-step explanation:

3 0
3 years ago
How can i solve this<br> (x+2)(2x+3)<br> step by step please
MrRissso [65]

Answer:

2x² + 7x + 6

Step-by-step explanation:

To solve this polynomial, you need to distribute/multiply, (x+2) with (2x+3).

You would first multiply (x) with 2x and 3. This would give you 2x² and 3x. You would then multiply 2 with 2x and 3. This would give you 4x and 6. You then add the like-terms, which are 3x and 4x, which gives you 7x. This would give you your final expression of 2x² +7x + 6.

(x+2)(2x+3)

2x²+ 3x + 4x + 6

2x² +7x + 6

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3 years ago
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