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ch4aika [34]
3 years ago
5

You use magnet to pick up nail, then use the nail to pick up a paper clip. What type of magnetism is the nail demonstrating?

Mathematics
1 answer:
bazaltina [42]3 years ago
5 0

Answer: Induced

Step-by-step explanation:

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Determine if the triangles are congruent
Dima020 [189]
Number eight is congruent 


8 0
3 years ago
Fruit basket is made with apple and oranges.the ratio of apples to oranges in a fruit basket is 2 to 3.if there are 45 pieces of
irina [24]
Apples to oranges = 2 to 3
total ratio = 2+3=5
number Of apples = 2/5 * 45
= 2*9 =18
pls mark me as brainliest
5 0
4 years ago
2 of 6
Kryger [21]

Answer:

£2112

Step-by-step explanation:

To find Gavin's share, sum the parts of the ratio, 4 + 1 = 5 parts

Divide the win by 5 to find the value of one part of the ratio.

£8800 ÷ 5 = £1760 ← value of 1 part of ratio, thus

4 parts = 4 × £1760 = £7040 ← Gavin's share

Now repeat the process with the ratio for his family

1 + 6 + 3 = 10 parts

£7040 ÷ 10 = £704 ← value of 1 part of the ratio, thus

6 × £704 = £4224 ← wife's share

3 × £704 = £2112 ← son's share

Difference = £4224 - £2112 = £2112

Thus his wife gets £2112 more than the son

4 0
3 years ago
Simplify.Your answer should contain only positive exponents.
zhannawk [14.2K]

Step-by-step explanation:

1) r^3r^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=r^{3+3}

=r^6

2) 3k^3k^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=3k^{3+3}

=3k^6

3) \left(3b^2\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=3^3\left(b^2\right)^3

=27\left(b^2\right)^3

=27b^6

4) \left(2m^3\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=2^3\left(m^3\right)^3

=8\left(m^3\right)^3

=8m^{3\cdot \:3}

=8m^9

5) \frac{3r^3}{r^2}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

=3r^{3-2}

=3r^1

=3r

3 0
3 years ago
Question part points submissions used solve the given differential equation by separation of variables. dx + e2xdy = 0
lina2011 [118]
Try this:
if given dx+e²ˣdy=0, then
dy=- \frac{dx}{e^{-2x}} \ =\ \textgreater \  \  \int dy=-\int e^{-2x}dx; \ =\ \textgreater \  \ y= \frac{1}{2}e^{-2x}+C;
4 0
3 years ago
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