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lys-0071 [83]
3 years ago
10

How do you Factor c(squared)-8c ??

Mathematics
2 answers:
8090 [49]3 years ago
7 0
You find a common factor which would be c.
c^2-8c
divide be c so it will look like this
c(c-8)
galina1969 [7]3 years ago
4 0
Is c^2-8c?
c^2-8c=c(c-8)
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Someone pls help and show ur work
ale4655 [162]

Answer:

8x8=16

easy

https://youtu.be/WYNfQabLpuk

6 0
3 years ago
What is the GCF of 6 and 15?<br><br><br> 3<br><br><br> 5<br><br><br> 6<br><br><br> 2
larisa [96]
The answer is three I believe
5 0
3 years ago
Read 2 more answers
What is the area of the rectangle?
STatiana [176]

Answer:

9x^2 25x+14

Step-by-step explanation:

using FOIL:

(x+2)(9x+7)

9x^2 +7x + 18x +14

9x^2 25x+14

4 0
3 years ago
Solve 3x2+7x+1=0 using the quadratic formula.
NNADVOKAT [17]

Answer:

x=\frac{-7+-\sqrt{37} }{6}

Step-by-step explanation:

This (±) goes between the -7 and \sqrt{37}

3x^{2} +7x+1=0

ax^{2} +bx+c

-b ± \sqrt{b^2-4ac}/2a

-7 ± \sqrt{(7)^2-4(3)(1)}/2(3)

-7 ± \sqrt{49-12}/6

-7 ± \sqrt{37}/6

7 0
3 years ago
At the beginning of a​ walk, roberto and juanita are 7.77.7 miles apart. if they leave at the same time and walk in the same​ di
dem82 [27]
Roberto overtakes Juanita at the rate of (7.7 mi)/(11 h) = 0.7 mi/h. This is the difference in their speeds. The sum of their speeds is (7.7 mi)/1 h) = 7.7 mi/h.

Roberto walks at the rate (7.7 + 0.7)/2 = 4.2 mi/h.
Juanita walks at the rate 4.2 - 0.7 = 3.5 mi/h.


_____
In a "sum and diference" problem, one solution is half the total of the sum and difference. If we let R and J be the respective speeds of Roberto and Juanita, we have
  R + J = total speed
  R - J = difference speed
Adding these two equations, we have
  2R = (total speed + difference speed)
  R = (total speed + difference speed)2 . . . . . as computed above
4 0
3 years ago
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