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MA_775_DIABLO [31]
3 years ago
11

The answer I got for this problem was 10.8 (multiplied 18 and 60 then divided by 100) however, it stated that my answer is incor

rect. Did I not round correctly or is my entire answer wrong?

Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0

9514 1404 393

Answer:

  30 mL

Step-by-step explanation:

The meaning of 60% solution is ...

  alcohol/(total volume) = 0.60

You are told the amount of alcohol is 18 mL, so you have ...

  (18 mL)/(total volume) = 0.60

Multiplying by total volume gives ...

  18 mL = 0.60 × (total volume)

Then dividing by 0.60, you have ...

  (18 mL)/0.60 = total volume = 30 mL

_____

<em>Additional comment</em>

You need to apply what you know about the real world to consider whether your answer makes any sense. If alcohol is a little more than half of the volume, and the amount of alcohol is 18 mL, then the total volume cannot be less than 18 mL. In fact, you expect it to be not quite double 18 mL.

An answer of 10.8 mL makes no sense in this context. You cannot have less total solution than you have of something that makes up a part of the total solution.

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5^(2x-1)+5^(x+1)=250<br> how do you solve?<br> thank you
zepelin [54]

Answer:

<em>x = 2</em>

Step-by-step explanation:

<u>Exponential Equations</u>

Solve:

5^{2x-1}+5^{x+1}=250

Separate each exponential:

5^{2x}5^{-1}+5^{x}5^{1}=250

Operating:

\displaystyle \frac{5^{2x}}{5}+5^{x}5=250

Multiplying by 5:

5^{2x}+25\cdot5^x=1250

Rearranging:

5^{2x}+25\cdot5^x-1250=0

Recall that:

5^{2x}=(5^{x})^2

(5^{x})^2+25\cdot5^x-1250=0

Calling

y=5^{x}:

y^2+25y-1250=0

Factoring:

(y-25)(y+50)=0

There are two possible solutions:

y=25

y=-50

Since

y=5^{x}

y cannot be negative, thus:

5^{x}=25=5^2

The solution is:

x = 2

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VARVARA [1.3K]

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You can write the equation as (x-0)² + (y-( -8))² = 2². From this, you can conclude that the center is (0,-8) and the radius is 2.

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Explanation:

The easiest way to do this is to make use of the 2-point form of the equation for a line. For points (x₁, y₁) and (x₂, y₂), the equation is ...

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Filling in your given points, the equation becomes ...

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After you fill in the values, it is a matter of simplifying the resulting equation.

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