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Nadusha1986 [10]
3 years ago
13

What is the integral of (2x^2+4)/(x^3+4x)

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0
Integral (2x^2+4)/(x^3+4x) dx =
integral (3x^2+4)/(x^3+4x) dx - integral (x^2)/(x^3+4x) dx =
integral d(x^3+4x)/(x^3+4x) -1/2*integral d(x^2+4)/(x^2+4)  =

ln|x^3+4x| -1/2*ln|x^2+4| + C =

ln|x*sqrt(x^2+4)| + C


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8 over 2x minus 4 over x squared
LuckyWell [14K]

Answer:

4x-4/x^2

Step-by-step explanation:

So we can first write out the equation.

It would be:

8/2x-4/x^2

First we can get a common denominator:

8/2x*x^2/x^2=8x^2/2x^3

and

4/x^2*2x/2x=8x/2x^3

Now we have

8x^2/2x^3-8x/2x^3

or

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We can divide everything by x

8x-8/2x^2

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3 years ago
Find what h equals please help ASAP THANK YOU!<br><br> 4h-1=3h+2
Sunny_sXe [5.5K]
H = 3.

FIRST STEP:
<span>Add 1 to both sides to get rid of the -1 on the left side.
4h-1 = 3h+2
</span><span>4h-1 (+1) = 3h+2 (+1)
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SECOND (FINAL) STEP:
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</span>4h(-3h) = 3h+3 (-3h)
h = 3
Hope this helps, sorry if it's hard to understand :)
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