What is the integral of (2x^2+4)/(x^3+4x)
1 answer:
Integral (2x^2+4)/(x^3+4x) dx = integral (3x^2+4)/(x^3+4x) dx - integral (x^2)/(x^3+4x) dx = integral d(x^3+4x)/(x^3+4x) -1/2*integral d(x^2+4)/(x^2+4) = ln|x^3+4x| -1/2*ln|x^2+4| + C = ln|x*sqrt(x^2+4)| + C
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