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Answer:
root 11
Step-by-step explanation:
AB = 6
BC = 5
AC = LET X
SO,
H²= P²+ B²
6²=X²+5²
36-25=X²
X= ROOT 11
Answer: 490 grams of the first alloy should be used.
30 grams of the second alloy should be used.
Step-by-step explanation:
Let x represent the weight of the first alloy in grams that should be used.
Let y represent the weight of the second alloy in grams that should be used.
A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is
0.15x and 0.2x
The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is
0.3y and 0.5y
If the alloy to be made contains 82.5 g of gold, it means that
0.15x + 0.3y = 82.5 - - - - - - - - - - - -1
The second alloy would also contain 113 g of lead. This means that
0.2x + 0.5y = 113 - - - - - - - - - - - - -2
Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes
0.03x + 0.06y = 16.5
0.03x + 0.075y = 16.95
Subtracting, it becomes
- 0.015y = - 0.45
y = - 0.45/- 0.015
y = 30
Substituting y = 30 into equation 1, it becomes
0.15x + 0.3 × 30 = 82.5
0.15x + 9 = 82.5
0.15x = 82.5 - 9 = 73.5
x = 73.5/0.15
x = 490
The solution of the equation are as follows:
x = 6 and y = -5
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<h3>How to solve the system of equation?</h3>
4x + 5y = -1
-5x - 8y = 10
Therefore,
20x + 25y = -5
-20x - 32y = 40
-7y = 35
y = -5
Hence,
4x + 5(-5) = -1
4x - 25 = -1
4x = -1 + 25
4x = 24
x = 24 / 4
x = 6
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(6,3x0,15)/1,5 = 0,945/1,5 = 0,63
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