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Dahasolnce [82]
3 years ago
11

8/m=6/15 use cross multiplying

Mathematics
1 answer:
Tema [17]3 years ago
7 0

Answer: m=20

Step-by-step explanation:

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What number is 9 times as much as 400 ? A 391 B 409 C 3,600 D 3,609​
Eddi Din [679]

Answer:

C.3600

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8 0
2 years ago
F(x)=square root 5x+7, g(x)= square root 5x-7 Find (f+g)(x)
o-na [289]

Answer: sqrt of 5x+7+ sqrt of 5x-7

Step-by-step explanation:

5 0
3 years ago
Every integer number is also a. Irrational number b. Whole number c. Natural number d. Rational number
const2013 [10]

Answer:

Option d

Step-by-step explanation:

Other options are not eligible because

a) Integers are not irrational

b)Whole numbers start from 0 and consists positive integers only.But integers consist negative integers also.

c)Natural number consists of positive integers only.

If the question had been asked as some integers are also, then options b) and c) could have been written . But in this case , it is asked every integer is also.

Thank you!

5 0
3 years ago
Which expression is represented by the diagram? ( Marked 1-4, I can't paste the question.)
wel

Answer:

-6-(-1)

Step-by-step explanation:

Since all the boxes are negative, and there are 6 boxes, the first part of the equation is -6.  Then since the last box is being taken away, we are subtracting it.  The last box is still negative though so the last part is -1.  Since -6 subtracted by -1 is -6-(-1), the answer is:

-6-(-1)

8 0
3 years ago
A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes
bekas [8.4K]

Answer:  1) 1/3,654     2) 3/406     3) 72,684,900,288,000      4) 120

<u>Step-by-step explanation:</u>

1)         First       and        Second         and         Third

  \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}

2)         First       and          Second

   \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}

3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}

4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}

8 0
3 years ago
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