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3 years ago

Solve for w -24=-3w+21

Mathematics

1 answer:

svlad2 [7]3 years ago

3 0

Answer:

w = 11.25

Step-by-step explanation:

To solve this problem, we are going to move all of the terms containing the variable w to the left side of the equation and all of the constant terms (ones with numbers only) to the right side of the equation.

w - 24 = -3w + 21

To do this, we should first add 24 to both sides of the equation.

w - 24 + 24 = -3w +21 + 24

If we simplify, we get:

w = -3w + 45

Next, we should add 3w to both sides of the equation.

w + 3w = -3w + 3w + 45

4w = 45

Finally, we can divide both sides by 4.

4w/4 = 45/4

w = 11.25

Hope this helps!

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What are three equivalent ratios for 18/6, 5/45, and 3/5?

mihalych1998 [28]

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3/5 : 6/10; 12/20; 24/40

hope that helps

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3 years ago

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The equations that must be solved for maximum or minimum values of a differentiable function w=f(x,y,z) subject to two constrai

sammy [17]

The Lagrangian is

$L(x,y,z,\lambda,\mu)=x^2+y^2+z^2+\lambda(4x^2+4y^2-z^2)+\mu(2x+4z-2)$

with partial derivatives (set equal to 0)

$L_x=2x+8\lambda x+2\mu=0\implies x(1+4\lambda)+\mu=0$

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$L_\mu=2x+4z-2=0\implies x+2z=1$

Case 1: If $y=0$ , then

$4x^2-z^2=0\implies4x^2=z^2\implies2|x|=|z|$

Then

$x+2z=1\implies x=1-2z\implies2|1-2z|=|z|\implies z=\dfrac25\text{ or }z=\dfrac23$

$\implies x=\dfrac15\text{ or }x=-\dfrac13$

So we have two critical points, $\left(\dfrac15,0,\dfrac25\right)$ and $\left(-\dfrac13,0,\dfrac23\right)$

Case 2: If $\lambda=-\dfrac14$ , then in the first equation we get

$x(1+4\lambda)+\mu=\mu=0$

and from the third equation,

$z(1-\lambda)+2\mu=\dfrac54z=0\implies z=0$

Then

$x+2z=1\implies x=1$

$4x^2+4y^2-z^2=0\implies1+y^2=0$

but there are no real solutions for $y$ , so this case yields no additional critical points.

So at the two critical points we've found, we get extreme values of

$f\left(\dfrac15,0,\dfrac25\right)=\dfrac15$ (min)

and

$f\left(-\dfrac13,0,\dfrac23\right)=\dfrac59$ (max)

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3 years ago

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Answer:

8) 76°
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Step-by-step explanation:

<em>Sum of exterior angles of any polygon is 360°</em>

<h3>Exercise 8</h3>

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stepladder [879]

Answer:

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Step-by-step explanation:

56/15

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Novosadov [1.4K]

Answer:

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Step-by-step explanation:

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This is a pretty short explanation, but there's not too much to it. Hope this helped :)

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3 years ago