Answer:
Area V
Step-by-step explanation:
Step-by-step explanation:
1) -5x<35
we divide both sides by 5
-5x/5<35/5
-x<7
we divide both sides by-1 to remove the negative sign
-x/-1<7/-1
x<7/-1
2) 2x>-42
we divide both sides by 2
2x/2>-42/2
x>-21
3) x/3≤-7
we multiply by 3 and we cancel 3
3(x/3)≤3(-7) we cancel the 3
x≤-21
4) x/-4≥-4
we do the same thing
x≥1
I believe it is 3. since it touches the x-axis in three areas
Answer:
1. -19x
3. 23 - 8x
5. -18x + 2y
Step-by-step explanation:
first: 3x - x = 2x
2x - 22x = -20x
-20x + x = -19x
second one:
8 - (-15) = 23
12x - 20x = -8 x
23 - 8x
third:
-10x - 8x = -18x
3y - y = 2y
-18x + 2y
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
