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xenn [34]
3 years ago
8

Evaluate P (5,3)A.15B.20C.60

Mathematics
2 answers:
atroni [7]3 years ago
3 0
Am i supposed to multiply? 5 times 3 equals 15 
valentinak56 [21]3 years ago
3 0

Answer:

_3^5\txterm{P}=60

Step-by-step explanation:

we have to evaluate P(5,3)

P(a, b) can be calculated as

_b^a\txterm{P}=\frac{a!}{(a-b)!}

_3^5\txterm{P}=\frac{5!}{(5-3)!}

=\frac{5\times 4\times 3\times 2!}{2!}=60

Hence, the correct option is 60 i.e

_3^5\txterm{P}=60

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A scale drawing of a field is shown below. The drawing uses a scale of 1 in. = 14 ft. What is the area of the actual field?
svp [43]

Answer:

D. 4,704 ft²

Step-by-step explanation:

Giving a scale of 1 in. = 14 ft, to find the actual area of the field represented by the triangular drawing above, convert the length of the base and height to the actual lengths of the field using the scale.

Height of drawing = 8 in.

Actual height = 8*14 = 112 ft

Base of drawing = 6 in.

Actual base = 6*14 = 84 ft

Area of the field = area of ∆

Area = ½*base*height

Area = ½*84*112

Area = 4,704 ft²

3 0
3 years ago
Finding domain f(x)=3x+1/x-5
arlik [135]
The function is undefinded if the denominator, x-5, equals 0.
So x-5 \neq 0 \\ 
x \neq 5.
The domain is x \neq 5.
In interval notation, this is (-infinity, 5) u (5, infinity).
4 0
3 years ago
What is the percent equivalent of 4.87? 0.0487% 0.487% 48.7% 487%
ahrayia [7]
The correct answer is 0.0487% Hope this helps! ;D
5 0
3 years ago
Find the value of the variable.
NemiM [27]

Answer:

x=y[base side of isosceles triangle]

x²+y²=19²

x=√{19²/2)}

x=13.44

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7 0
3 years ago
Find the inverse of the given function. (pictured below)
zavuch27 [327]

Answer:

4

3

0

Step-by-step explanation:

f(x) = y = -1/2 × sqrt(x+3)

2y = -sqrt(x+3)

4y² = x + 3

x = 4y² - 3

now renaming this, so that the normal symbols and names are used for this function definition, so that the input variable is called "x" :

f-1(x) = 4x² - 3

basically, just by itself, this function would be defined for all possible real values of x.

but because it is the inverse of the original function, which generates only values of y<=0, then for the inverse function that same range applies for its input variable x

x<=0

4 0
3 years ago
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