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Nastasia [14]
3 years ago
8

10 times as many as_hundred is 60hundred or _ thousands

Mathematics
1 answer:
Sloan [31]3 years ago
6 0
60000 is the answer  for your problem
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Joanne buys a car for $1500 after 12 months Joanne is forced to sell the car for 10% less than what she brought it for, how much
MAVERICK [17]

Answer:

$1350

Step-by-step explanation:

Given she sold the car 10% less than what she bought it, amount she sold the car will be 10% of the amount she bought the car subtracted from the amount she bought he car .

She bought the car for $1500

Therefore,

10% of $1500

10% /100% x $1500

0.1 x $1500

$150

Now , amount she sold the car = $1500 - $150

= $1350

She sold the car for $1350

7 0
4 years ago
Jenn recorded the favorite school subject of students at her school. she surveyed 700 students. how many more students chose Eng
sergij07 [2.7K]
105 students chose English than science
5 0
3 years ago
Read 2 more answers
Carmen deposits $700 into an account that pays simple interest at a rate of 3% per year. How much interest will she be paid in t
VLD [36.1K]
First we need to find what 3% of 700 is.  We know 10% is 70, 5% is 35, so we need to find out what 3% is.  If you don't know how to calculate percentages of a number, I recommend starting with 10%.  This way you know 10% of the number is 70, so you will also know that 1% of the number is 7.  7 x 3 = 21.  So 3% of 700 is 21.  Since it was over 6 years, we multiply 21 x 6.  That gives us 126.  She will be paid $126 in interest in the first six years.
4 0
4 years ago
Read 2 more answers
Please help which one is it!!
sasho [114]
Last one and first. You can find out why by isolating the cube root and cubing both sides.
6 0
2 years ago
Read 2 more answers
If y has moment-generating function m(t) = e 6(e t −1) , what is p(|y − µ| ≤ 2σ)?
Lostsunrise [7]
Since \mathrm M_Y(t)=e^{6(e^t-1}, we know that Y follows a Poisson distribution with parameter \lambda=6.

Now assuming \mu,\sigma denote the mean and standard deviation of Y, respectively, then we know right away that \mu=6 and \sigma=\sqrt6.

So,

\mathbb P(|Y-\mu|\le2\sigma)=\mathbb P(6-2\sqrt6\le Y\le6+2\sqrt6)=\dfrac{66366}{175e^6}\approx0.940028
6 0
4 years ago
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