10 times as many as_hundred is 60hundred or

At Elisa's printing company, there are two kinds of printing presses: Model A, which can print 70 books/ day, and model B, which

Dmitrij [34]

Answer:

9 Model As.

Step-by-step explanation:

Let A represent Press A and let B represent Press B.

So, they own 14 total presses. This means that:

$A+B=14$

They can print 905 books per day, in other words, since A prints 70 per day and B prints 55 per day:

$70A+55B=905$

This is now a system of equations. Solve by substitution. From the first equation, subtract B from both sides:

$A=14-B$

Substitute this into the second equation: "

$70(14-B)+55B=905$

First, we can divide everything by 5 to simplify things:

$14(14-B)+11B=181$

Distribute the left:

$196-14B+11B=181$

Combine like terms:

$-3B+196=181$

Subtract 196 from both sides:

$-3B=-15$

Divide both sides by -3

$B=5$

So, the company has 5 Model B presses.

Which means that the company has 14-5 or 9 Model A presses.

And we're done!

3 0

3 years ago

Workers have been down the street installing two blinking red lights in front of the fire station. The two lights are always tur

daser333 [38]

Answer:

After 88 seconds, they will blink together.

Step-by-step explanation:

Time after which the first light blinks = 8 seconds

Time after which the second light blinks = 22 seconds

Initially, both the lights blink together.

To find:

The time at which they will blink together again.

Solution:

Let us have a look at the time after which each light will blink.

First light will blink after:

8 s, 16 s, 24 s, 32 s, 40 s, 48 s, 56 s, 64 s, 72 s, 80 s, <em>88 s</em>, 96 s, 104 s, ......

Second light will blink after:

22 s, 44 s, 66 s, <em>88 s</em>, 110 s, .....

It can be seen that common time is 88 second, at which the both will blink together.

So, the answer is <em>88 s.</em>

This answer can also be computed by taking the LCM (Least Common Multiple) of both the numbers i.e. 8 and 22.

Using the factorization method:

$8=\underline{2}\times 2\times 2$

$22=\underline{2}\times 11$

Common is 2.

Therefore the LCM will be:

$2\times 2\times2\times 11 = \bold{88}$

So, the answer is <em>88 s.</em>

5 0

3 years ago

A church rings its bells every 15 minutes, the school rings its bells every 20 minutes and the day care center rings its bells e

ankoles [38]

Answer:

As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).

Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.

Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.

So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!

Step-by-step explanation:

7 0

3 years ago

Can someone please help me???

bazaltina [42]

A. (4)5 x (4)4 = 36 OR 4(5 x 4) = 36
b. No you would not. 5(5 x 4) = 45 which is out of your budget.

8 0

3 years ago

ASAP!!!!!!!!!!!!

Phoenix [80]

The two transformations for fx and gx would be to shift by 6 units and also go up by 18.

<h3>What is a transformation?</h3>

This is the term that is used in mathematics to describe the manipulation of a line or a shape.

a. The possible transformations that can be gotten here would be to shift to the left by 6 units from what we have in the graph and also shift to the top by 18.

<h3>b. How to solve for K in the transformation</h3>

g of x = f(x - k) then

g(x)= f(x) + k

C. The value of k should be based on the way it changes based on the given points.

Vertically, g(x)=f(x) +18

Horizontally , g(x)=f(x-6)

10 times as many as_hundred is 60hundred or _ thousands