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Pavel [41]
3 years ago
13

3 assembly lines can fill 24 orders for a shipping company in 10 hours. At the same rate, how many orders could 7 assembly lines

fill in 5 hours for the company?
Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0
3 assembly lines can fill 24 orders in 10 hours , therefore in 1 hour 3 assembly lines can fill 2.4 orders (24/10) , consequently, 1 assembly line can fill 0.8 orders (2.4/3)  in 1 hour. Therefore, 7 assembly lines can fill 5.6 (7×0.8)orders in an hour and thus the 7 assembly lines in 5 hours would fill (5.6 ×5)= 28 orders.
Therefore, the answer is 28 orders
maria [59]3 years ago
6 0
<span>28. This is because each assembly line makes 8 orders for ten hours. That means for every hour, an assembly can make 0.8 orders. When you multiply that by 5 hours and 7 assembly lines you get 28 orders</span>
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A right rectangular prism has a length of 9, a width of 4, and a height of 5. How many unit cubes can fit in the prism?
Serjik [45]

Answer:

The answer is 54 cubes.

Step-by-step explanation:

5 0
3 years ago
What is the angle of rotation of the image?<br>A. 60°<br>B. 90°<br>C.120°<br>D. 180°<br>​
lisov135 [29]

Answer:

It would be great if you would provide the image itself. I will totally answer your question.

4 0
3 years ago
Help please thanks in advance
Westkost [7]
A) In Part 1 to part 2 the bus had its farthest distance. At part 2 the bus stayed steady time went by. Part 3 to 4 was decreasing distance. part 4 was constant. Then again at part 5 the distance was increasing

B) 

1 - increasing

2 - constant

3 - decreasing

4 - constant

5 - increasing

C) Non-linear, because the graph has a curve, for it to be linear it must be a straight line.

Hope this Helps :)
8 0
2 years ago
Element X is a radioactive isotope such that every 51 years, its mass decreases by half. Given that the initial mass of a sample
pychu [463]

Answer: It will take 6 years for 7500 grams of X to reach 6900 grams.

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  

a - x = amount left after decay process  

a) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

51=\frac{0.69}{k}

k=\frac{0.69}{51}=0.0135years^{-1}

b) for  7500 g to reach to 6900 g

t=\frac{2.303}{0.0135}\log\frac{7500}{6900}

t=6years

It will take 6 years for 7500 grams of X to reach 6900 grams.

5 0
2 years ago
A substance with a half life is decaying exponentially. If there are initially 12grams of the substance and after 70 minutes the
dybincka [34]

Answer:

Step-by-step explanation:

Use the half life formula

N=N_0e^{kt} where N is the amount after decay, No is the initial amount, e is Euler's number, k is the decay constant, and t is the time in minutes. For us, the first equation looks like this:

7=12e^{k(70)} and we will solve that for k and then use that value of k in the second equation to find time.

Begin by dividing 7 by 12 to get

\frac{7}{12}=e^{k(70)} Now take the natural log of both sides since the natural log and that e are inverses. The e then disappears:

ln(\frac{7}{12})=k(70)

Plug the left side into your calculator and then set it equal to the right side, giving us:

-.5389965007=70k

Divide both sides by 70 to get the k value of

k = -.00769995

Now the second equation looks like this:

2=12e^{(-.00769995)t where t is our only unknown now that we know k.

Begin by dividing both sides by 12 to get

\frac{1}{6}=e^{-.00769995t and take the natural log of both sides again to eliminate the e:

ln(\frac{1}{6})=-.00769995t

Take care of the left side on your calculator to get

-1.791759469 = -.00769995t and divide both sides by -.00769995 to get

t = 232.697 minutes

4 0
2 years ago
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