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2 years ago

2/5% as a fraction in it's simplest form

Mathematics

1 answer:

Llana [10]2 years ago

4 0

Answer:

Here is the ans...hope it helps:)

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F(x)=9x-6 what is f(1)

Leto [7]

Hello,

Shall we begin?

F(x)=9x-6

F(1) = 9 * 1 - 6
F(1) = 9 - 6
F(1) = 3

Answers: 3

8 0

3 years ago

Solve the equation: k^2+5k+13=0

mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\$

From the question

a = 1 , b = 5 , c = 13

So we have

$k = \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)} \\ = \frac{ - 5 \pm \sqrt{25 - 52} }{2} \\ = \frac{ - 5 \pm \sqrt{ - 27} }{2} \: \: \: \: \: \: \\ = \frac{ - 5 \pm3 \sqrt{3} \: i}{2} \: \: \: \: \: \:$

Separate the solutions

$k_1 = \frac{ - 5 + 3 \sqrt{3} \: i }{2} \: \: \: \: or \\ k_2 = \frac{ - 5 - 3 \sqrt{3} \: i}{2}$

The equation has complex roots

Separate the real and imaginary parts

We have the final answer as

$k_1 = - \frac{5}{2} + \frac{3 \sqrt{3} }{2} \: i \: \: \: \: or \\ k_2 = - \frac{5}{2} - \frac{3 \sqrt{3} }{2} \: i$

Hope this helps you

8 0

2 years ago

WHAT IS THE CORRECT VOCAB TERM FOR THE FOLLOWING DEFINITION:

yawa3891 [41]

I believe the term would be radicand

4 0

3 years ago

Read 2 more answers

Can you help me please

xenn [34]

(2, -3)

The Answer is A

3 0

3 years ago

What is the area of yhe following circle?either an exact answer in terms of or use 3.14 for and enter your ansert as a decimal

Harman [31]

Answer and Step-by-step explanation:

If the radius is 5, then we can plug 5 into the area of a circle equation.

A = $\pi r^{2}$

A = $\pi (5)^{2}$

A = 25 $\pi$

The area of a circle with radius 5 is 25 $\pi$ .

#teamtrees #PAW (Plant And Water)

8 0

3 years ago

2/5% as a fraction in it's simplest form​

2/5% as a fraction in it's simplest form