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alisha [4.7K]
3 years ago
13

Does anyone know the answer to this?

Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

Step-by-step explanation:

 

Percent: The percent is the number with the % symbol: 20%.

 

Base: The base is the whole amount, which in this case is unknown.

Amount: The amount based on the percent is 40

Base = unknown

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Briana drew a rectangle with a width 5 inches shorter than its length. She measured the perimeter of the rectangle and found it
Zigmanuir [339]
P = 2(L + W)
P = 14
W = L - 5

14 = 2(L + L - 5)
14 = 2(2L - 5)
14 = 4L - 10
14 + 10 = 4L
24 = 4L
24/4 = L
6 = L.......the length is 6 inches

W = L - 5
W = 6 - 5
W = 1 <=== the width is 1 inch
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3 years ago
Fine the missing exponent
alisha [4.7K]

Answer:

hi

Step-by-step explanation:

it is simple

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Answer:

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Step-by-step explanation:

8 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
4.5m equales how many cm
lara31 [8.8K]
When i converted it 4.5 meters is 450 centimeters
7 0
3 years ago
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