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2 years ago

Find the midpoint of BD.

Mathematics

1 answer:

Mrac [35]2 years ago

8 0

It’s a black picture......

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2 years ago

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3 years ago

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10. Use the properties of exponents to simplify the expression:

aivan3 [116]

<h3><u>Answer</u> :</h3>

$\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}$

Let's solve !

$:\implies\sf\:25^{\frac{3}{2}}$

$:\implies\sf\:(\sqrt[2]{25})^3$

$:\implies\sf\:5^3$

$:\implies\boxed{\bf{\red{125}}}$

<u>Hence, Oprion-D is correct</u> !

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3 years ago

OC and OR are similar. Find the length of QP.

Elena L [17]

Given:

Circle C and circle R are similar.

The length of arc AB is $s = \frac{22 \pi}{9}$

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s, r and $\theta$ is

$arclength = 2\pi r \frac{\theta}{360}$

where,

s be the length of the arc

r be the radius

$\theta$ be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

$2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}$

or, $2r \frac{\theta}{360} = \frac{22}{9}$ [ eliminating $\theta$ from both side]

or, $\theta = \frac{(22)(360)}{(9)(2)(4)}$

or, $\theta = 110^\circ$

Again,

For circle R

Taking, r = 6 and $\theta = 110^\circ$ we get,

The length of arc QP is

$arc length = 2\pi (6)(\frac{110}{360} )$

or, $arclength = \frac{11 \pi}{3}$

Hence,

The length of QP is $\frac{11 \pi}{3}$ . Option C.

5 0

3 years ago

Plz hurry!!!! thank you!!!!

tatyana61 [14]

Step-by-step explanation:

Since SP=TR, the differnce of PR and ST 24-15 divided by 2 is the length of PD (4.5)

Try to understand the rest from the attached picture

3 0

3 years ago