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harkovskaia [24]
3 years ago
12

Which similarity postulate or theorem let’s you conclude that JKL = MNO?

Mathematics
1 answer:
Ede4ka [16]3 years ago
5 0
The answer is angle angle
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Please help. I will give you brainly
ollegr [7]
The slope of the line shown is m=1/6
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1 year ago
The velocity of a particle moving back and forth on a line is vequalsStartFraction ds Over dt EndFraction equals6 sine (2 t )Sta
max2010maxim [7]

Answer:

s = 6 m

Step-by-step explanation:

The value of the velocity v is given as:

v = \frac{ds}{dt} = 6 sin(2t) m/s

To find s, we have to integrate and apply the initial values of s = o when t = 0:

\frac{ds}{dt} = 6 sin(2t)\\\\\int\limits^s_0 {ds} = \int\limits^t_0 {6sin(2t)} \, dt\\\\s|^s_o = -3cos(2t)|^t_o\\\\s - 0 = -3cos(2t) -(-3cos(0))\\\\s = -3cos(2t) + 3(1)\\\\s = -3cos(2t) + 3

When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

s = -3cos(π) + 3

s = -3(-1) + 3

s = 3 + 3

s = 6 m

4 0
4 years ago
What is the slope of this line
kondaur [170]
The slope is-2/-2 because of the y and x axis


7 0
3 years ago
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Bob is driving along a straight and level road toward a mountain. At some point on his trip, he measures the angle of elevation
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Tan 21 44 =  h / 13428.7
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Height =   5353 feet
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3 years ago
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