<span>The integral of (x^2 + 6x)dx is 1/3x^3 + 3x^2 + c.
Because this is not an integration with specific bounds, you must include a constant at the end.
In general, to integrate, add 1 to the exponent of x and then whatever number is the exponent of x, divided the number in front of x by that.</span>
Answer:
a = -10
Step-by-step explanation:
-0.4a + 3 = 7
subtract 3 from each side
-0.4a + 3-3 = 7-3
-.4a = 4
Divide each side by -.4
-.4a/ -.4 = 4/-.4
a = - 10
All you'd do is divide by 4 on both sides,
4/4 = 1
12/4 = 3
Your Answer:
x < 3
