Multiplying fractions: 5 1 — x

Last month in the village of 125 people we’re issued a parking ticket. This month only 83 people were issued one. What was the p

natita [175]

Answer:

the percent reduction is 33.6% and the number of people who were issued a parking ticket are 42.

Step-by-step explanation:

Given:

Last month in the village of 125 people were issued a parking ticket.

This month only 83 people were issued one.

Now, to find the percent reduction from this month to last month and the number of people who were issued a Parking ticket.

So, the reduction of the number of people who were issued a Parking ticket from this month to last month are:

125 people - 83 people = 42 people.

Thus, 42 people reduction from this month to last month.

Now, to get the percent reduction:

$\frac{42}{125}\times 100.$

$=\frac{4200}{125}$

$=\ 33.6\%$

Therefore, the percent reduction is 33.6% and the number of people who were issued a parking ticket are 42.

7 0

3 years ago

A taco stand sells tacos for $3.25 each. The stands expenses for the day are $210. Define your variables and write an inequality

Julli [10]

Given:

Let P= profit
let n= no. of tacos sold per day

Sol'n:

P= 3.25n-210
the profit needs to be positive, thus

3.25n>210

n>210/3.25

n> 64.615

they can only sell whole tacos, therefore they must sell at least 65 tacos to make a profit and that profit is:

P=3.25n-210

P=3.25*65 - 210

P= 211.25 -210

P= 1.25

$1.25 profit

3 0

3 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,