Which value is an input of the function?<br> -14<br> -2<br> 0<br> 4

VLD [36.1K]

Answer:

Step-by-step explanation:

Part A: 5/26

Part B: 5/26+ 1/2 which is 18/26 or 9/13

Part C: 5/26 +21/25. 'without replacing' means there is one less option in the bag. So denominator becomes 26-1=25. Numerator is 21 because there are a total of 21 consonants in the alphabet. Since we removed a vowel and not a consonant, it will remain 21.

7 0

3 years ago

Given the two expressions shown below:

AlladinOne [14]

$\sqrt3\ is\ irrational\\\\\sqrt2\ is\ irrational\\\\\sqrt6\ is\ irrational\\\\therefore\\\\A.\ \sqrt3+\sqrt2\ is\ irrational\ and\ B.\ \sqrt3+\sqrt6\ is\ irrational$
Answer: Both are irrational.

3 0

3 years ago

This is super confusing plz help???

netineya [11]

Answer:

None. She gave half to one person then the other half to another person.

Step-by-step explanation:

Hope this is correct, if not feel free to let me know. I'm sorry in advance if this is wrong.

4 0

3 years ago

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Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

Free poitnssssssssssssssssssssssssssssssss

puteri [66]

Thank you kind sir

The purpose of life is to learn and pass on what you have learned. We all started out a cell. That cell then became two. All throughout time people have learned and passed on their knowledge. There is no real purpose to life except to learn and then pass on. From birth to death we learn and pass it on and in years, later on, we will know more and more. Never stopping this cycle. Until we know too much and the world ends from the power and fighting of the powers of human exists.

4 0

3 years ago

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Which value is an input of the function? -14 -2 0 4