Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
Answer:
Nolan correctly identified the square numbers before and after 18.
The square roots of them are 4 and 5.
Clearly, square root of 18 should lie between 4 and 5 only.
He, then carefully squared 4.1, 4.2, 4.3 etc. and identified that 4.3 squared is nearer to 18.
Since, Nolan is finding estimated square root, his steps are cool and he didn't make any error.
We are given with:
Average height of plants to be at least 73 inches
Three plants with heights of
70, 71, 72
The inequality that can be used to determine the possible heights of the fourth plant is:
(70 + 71 + 72 + x) / 4 ≥ 73
Solving for x
x ≥ 79
Answer:
number 3
Step-by-step explanation:
