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3 years ago

Given: F(x) = 2x - 1; G(x) = 3x + 2; H(x) = x^2

Mathematics

1 answer:

grin007 [14]3 years ago

6 0

Answer:

The answer to your question is: the answer is the second one

Step-by-step explanation:

Data

F(x) = 2x - 1

G(x) = 3x + 2

H(x) = x²

Find H(x + a) - H(x)

H(x + a) = (x+a)² substitution

= x² + 2xa + a² expanding

H(x + a) - H(x) = x² + 2xa + a² - x² simplifying

H(x + a) - H(x) = 2xa + a² or a² + 2ax

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love history [14]

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3 years ago

--8x < 32. How can I solve this

Vlada [557]

Answer:

<u>Divide by -8</u> on both sides. <u>Flip</u> the inequality.

Step-by-step explanation:

You didn't provide any answer choices, but here's how you would solve this:

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4 0

2 years ago

Please answer this (photo below)

lozanna [386]

Answer:

Please see attached image for the graph

Step-by-step explanation:

To graph the elevation versus time, we start by plotting the first point at time zero (when the climb begins) when Zane is 20 meters below the edge (-20 meters). This corresponds to the point (0, -20).

One second later (1 in the horizontal axis), Zane has moved up 4 meters, now reaching -16 meters. This is the point (1, -16) on the graph.

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you can go on like this plotting more points on the graph.

Please see the attached image that illustrates this and shows the appropriate line that represents Zane's position versus time (pictured in red)

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3 years ago

What is the complete factorization of the polynomial function over the set of complex numbers? f(x)=x^3+3x^2+16x+48

Tamiku [17]

Answer: $(x+3)(x+4i)(x-4i)$ is the required factorization of f(x).

Step-by-step explanation:

To factor the expression we must first group the terms and then take out common from these groups

$f(x)=x^3+3x^2+16x+48=(x^3+3x^2)+(16x+48)$

Taking $x^2$ common from first group and the 16 from second group we get:

$f(x) = x^2(x+3)+16(x+3) = (x+3)(x^2+16)$

Now, to factor in complex from we have to break term $x^2+16$

$f(x)= (x+3){x^2-(-4i)^2}$

As, $i^2 = -1 , therefore (-4i)^2 = 16i^2 =-16$

Also using identity $a^2-b^2 =(a+b)(a-b)$

On solving

$f(x) = (x+3)(x+4i)(x-4i)$

$(x+3)(x+4i)(x-4i)$ is the required factorization of f(x).

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3 years ago