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igor_vitrenko [27]
3 years ago
10

Suppose that Y and Z are points on the number line.

Mathematics
1 answer:
alexgriva [62]3 years ago
5 0

We have been given that Y and Z are points on the number line.   The length of segment YZ is 9 units and Y lies at -12. We are asked to find the location of point Z.

Since Y and Z are located on number line, so Z can be either on left side of Y or on right side of Y.

When Z is on left side of Y, then we can set an equation as:

Y-Z=9

-12-Z=9

-12+12-Z=9+12

-Z=21

Z=-21

Therefore, the location of Z will be -21.

When Z is on right side of Y, then we can set an equation as:

Z-Y=9

Z-(-12)=9

Z+12=9

Z+12-12=9-12

Z=-3

Therefore, the location of Z will be -3.

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Answer:

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Step-by-step explanation:

Given

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r \to Mary hits

Required

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If Mary is to win, then Peter has to lose his throw

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p' = 1 - p

So, the probability that Mary wins is:

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P(Mary) = (1 - p) * r

6 0
3 years ago
What is 8 divided by 4
Gennadij [26K]
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8 0
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morpeh [17]

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A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t
Sati [7]

Answer:

\frac{2}{7}

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

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Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = \frac{1}{7}

Remaining fuel after driving around the city = 1 - \frac{1}{7}

                                                                         =    \frac{7 - 1}{7}  = \frac{6}{7}

According to question:

As from the rest of the gas in the car that is \frac{6}{7}, the car can complete 3 trip to Ottawa  which means,

By unitary method:

The car can complete 3 trip by using = \frac{6}{7} tank of gas.

The car can complete 1 trip by using =  \frac{6}{7} \div 3

                                                             =\frac{6}{7} \times\frac{1}{3}

                                                             =  \frac{6}{21}

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Thus, \frac{2}{7} tank of gas used for each complete trip to Ottawa.

5 0
3 years ago
What is the sum of the arithmetic series below?
Irina-Kira [14]
Hello : 
the common ratio is r = -95-(-100)=5
the general terme is : un= u1+(n-1)r
un = -100 +(n-1)(5)
un =-100 +5n-5
un = 5n-105
The last term is : 100
un =100
5n-105 = 100
5n =205
n = 41 (Number of terms)
The last term is : u 41
<span>the sum is : S= (41/2)(-100+100)=0</span>
5 0
3 years ago
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