Answer:
Eq: (x+a/2)²+(y+1)²=(a²-8)/4
Center: O(-a/2, -1)
Radius: r=0.5×sqrt(a²-8)
Mandatory: a>2×sqrt(2)
Step-by-step explanation:
The circle with center in O(xo,yo) and radius r has the equation:
(x-xo)²+(y-yo)²=r²
We have:
x²+y²+ax+2y+3=0
But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4
And
y²+2y+3=y²+2y+1+2=(y+1)²+2
Replacing, we get:
(x+a/2)²-a²/4+(y+1)²+2=0
(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4
By visual inspection we note that:
- center of circle: O(-a/2, -1)
- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)
-7y-4x=17y-2x=53
-4x=24y-2x=53
-2x=24y=53
24y+2x=53
You would have to solve one at a time.
y=53/24
y=2.21
x=53/2
x=26.5
Answer:
Im pretty sure the answer is 410 2/3
I hope this helped to answer your question.
Have a great day! :)
Answer: -2.1p + 1.7
2.4 - 6p - 0.7 + 3.9p
Subtract 6p from 3.9p. (-2.1p)
Subtract 0.7 from 2.4. (1.7)