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Andrews [41]
3 years ago
14

Diedre drew a quadrilateral with 4 right angles 4 sides are the same length what kind of polygon did diedre draw

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0
A. square
explanation: a square has four equal side lengths and four right angles, the other shapes do not fit the criteria 
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-7y + 2 = -75<br> Step by Step
attashe74 [19]

Answer:

11

Step-by-step explanation:

2+75= 7y

77 = 7y

77/7 = 7y/7

y = 11

8 0
4 years ago
Read 2 more answers
If f(x)=2x^2+1,what is f(x) when x=3
REY [17]

Answer:

f(3) =19

Step-by-step explanation:

f(x)=2x^2+1

Let x = 3

f(3) = 2(3)^2 +1

Exponents first

        =2(9) +1

Then multiply

         =18+1

         =19

4 0
3 years ago
What is the compliment of a 62° angle.
krok68 [10]

Answer:

28°

Step-by-step explanation:

complimentary angles = their sum is 90.

so to find the complimentary angle of 62, just subtract it from 90.

90-62 = 28

your answer is 28°

good luck with your schoolwork/homework!

---------------------------------------------------------------------

apologies in advance for incorrect answers or bad explanations.

3 0
3 years ago
After Ricardo received his allowance for the week, he went to the mall with some friends. He spent half of his allowance on a ne
ad-work [718]
Lets work backwards, he had $5 after it all, and spent $1.25 on a snack, so we add that to the remainder, which is $6.25. then he spent half of that on whatever stuff he likes, so add $6.25 and $6.25, which is $12.50
6 0
3 years ago
Read 2 more answers
In circle O, m∠R = 30.8°. Find m∠NOQ.
nordsb [41]

Given:

In circle O, m∠R = 30.8°.

To find:

The m∠NOQ

Solution:

Central angle theorem: According to this theorem, the central angle is always twice of subtended angle on the same arc.

Angle NOQ and angle NRQ are on the same arc but ∠NOQ is the central angle and ∠NRQ is the subtended angle on the arc NQ.

Using central angle theorem, we get

m\angle NOQ=2\times m\angle NRQ

m\angle NOQ=2\times m\angle R

m\angle NOQ=2\times 30.8^\circ

m\angle NOQ=61.6^\circ

Therefore, m\angle NOQ=61.6^\circ.

4 0
3 years ago
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