Answer:
-6s-c+1
Step-by-step explanation:
(-3s-4c+1)+(-3s+3c)
We have been given the above expression. To find the sum, we simply collect the like terms and combine them;
(-3s-4c+1)+(-3s+3c) = -3s + -3s -4c + 3c + 1
-3s + -3s -4c + 3c + 1 = -3s - 3s + 3c - 4c + 1
-3s - 3s + 3c - 4c + 1 = -6s - c + 1
Therefore;
(-3s-4c+1)+(-3s+3c) = -6s-c+1
First, find out how much each man works. If eight men take 10 days to build 150 m of wall, then that means that it takes 80 man days to build 150 m. One Man day is then 150÷80, in other words 1.875. If eight men have already been working for six days, then they have spent 8×6 man days, 48. 48 men days times 1.875 m of wall per man day equals 90 m of wall have been built. So, you have four days left to build the remaining 60 m of wall as well as 45 extra meters, in other words, 105 m total. 105 m divided by four days equals 26.25 m need to be built every day. Since one man builds 1.875 m of wall every day, to find the number of men total you need for the last four days, take 26.25÷1.875, Which equals 14 exactly. 14 is not the answer however, because it’s asking how many more men you need. Since you already have eight, you need six more to make 14
The answer is six more men
Answer:
∠ A ≈ 48°
Step-by-step explanation:
Using the Cosine rule to find an angle
cosA = 
with a = 10, b = 13 and c = 11
cosA = 
= 
= 
, thus
A = 
( ) ≈ 48° ( to the nearest degree )
