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UNO [17]
3 years ago
9

Find the circumference of a circle. Geometry

Mathematics
1 answer:
MaRussiya [10]3 years ago
7 0
The circumstances of the circle is 62.83
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How do I Simplify 4a – 7b + 2ab – a + b (I need step by step cause I'm trying to learn this)
Alex

Step-by-step explanation:

Ok. First of all, we need to follow the order of operations: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. We don't have any parentheses, exponents, or division to resolve, so you can skip those. So now you have: Multiplication, Addition, and Subtraction. We have multiplication in each term, but each term is fully simplified, so we have Addition and Subtraction left.

With that out of the way, let's go ahead and rearrange this equation so it is easier to solve. (<em>Note: we can only rearrange terms that are positive because subtraction is not commutative. But we can turn negative terms into "positive" terms by the method shown below.</em>)

4a - 7b + 2ab - a + b

4a + (-7b) + 2ab + (-a) + b (<em>Now the terms are all positive, so we can rearrange them, but they still have the same value.</em>)

4a + (-a) + 2ab + (-7b) + b

3a + 2ab + 7b

And there we go. Our answer is fully simplified. If you can understand this, you'll be able to simplify without isolating and rearranging the terms each time.

Hopefully this was helpful and not confusing.

4 0
3 years ago
Find the trig ratio. Reduce to<br> lowest terms.<br> 10<br> 24<br> sin A =
Luba_88 [7]

The value of sin A is equal to \frac{5}{13}.

<h3>RIGHT TRIANGLE</h3>

A triangle is classified as a right triangle when it presents one of your angles equal to 90º.  In this triangle from the trigonometric ratios or the Pythagoras Theorem (hypotenuse^2=(side_1)^2+(side_2)^2), it is possible finding angles or sides.

<h3>Trigonometric Ratios</h3>

The main trigonometric ratios for a right triangle are presented below.

sin\alpha =\frac{opposite \; side}{hypotenuse}

cos\alpha =sin\alpha =\frac{adjacent\; side}{hypotenuse}

tan\alpha  =\frac{opposite \; side}{adjacent\; side}

The question asks the sin A. First, you should find the hypotenuse from Pythagoras Theorem.

hypotenuse^2=(10)^2+(24)^2\\ \\ hypotenuse^2=100+576\\\\ hypotenuse^2=676\\ \\ hypotenuse=26

Now you can find sin A.

sin\A=\frac{10}{26}=\frac{5}{13}

Learn more about trigonometric ratios here:

brainly.com/question/11967894

#SPJ1

3 0
2 years ago
To the nearest whole degree, what angle measure has a sine of 0.3535? SOMEBODY HELP
Bas_tet [7]
The angle is sin inverse 0.3535 which is around 21 degrees
5 0
3 years ago
Jim had some dimes, quarters, and nickels. First, he counted only the dimes and quarters and found that he had 9 coins. Then, he
Olegator [25]

Answer:

$1.90

Step-by-step explanation:

Represent the numbers of nickels, dimes and quarters by n, d and q.

Then: d + q = 9, or q = 9 - d.

Also, n + d = 10

Lastly, n + d + q = 15.

Let's substitute 9 - d for q in the equation immediately above:

n + d + (9 - d) = 15, or n + 9 = 15.  Then n must be 6.

In summary, Jim has 6 nickels, (10 - 6) dimes and (9 - 4) quarters, or:

                                    6 nickels, 4 dimes and 5 quarters

Thus, he has 5($0.05) + 4($0.10) + 5($0.25), or

                         $0.25   +   $0.40   + $1.25, or          $1.90

7 0
3 years ago
A set of composite numbers less than 12 .express it in listing and set builder methods​
marusya05 [52]

Given:

A set of composite numbers less than 12.

To find:

The set by listing and set builder methods​.

Solution:

Composite number: A positive integer is called a composite number if it has at least one divisor other than 1 and itself.

Composite numbers less than 12 are 4, 6, 8, 9, 10.

By using the listing method , the given set can be expression as:

Set = {4, 6, 8, 9, 10}

The numbers 4, 6, 8, 9, 10 are greater than 1, less than 12 and non prime numbers.

By using set builder method, the given set can be expression as:

Set = \{x|x\neq P,1

Therefore, the list and set builder notation of the given set are {4, 6, 8, 9, 10} and \{x|x\neq P,1 respectively.

5 0
3 years ago
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