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postnew [5]
3 years ago
7

What is the sign of 3x y3xy3, x, y when x>0x>0x, is greater than, 0 and y<0y<0y, is less than, 0?

Mathematics
2 answers:
jekas [21]3 years ago
4 0

Answer:

Negative

Step-by-step explanation:

We\ have\ to\ find\ sign\ of\ 3xy^3\\\\x>0\ and\ y0,y

Vladimir [108]3 years ago
3 0

Answer:

Negative

Step-by-step explanation:

Positive x positive= positive

Positive x negative= negative

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Ilya [14]

Answer:

13.8

Step-by-step explanation:

Recall the trigonometric ratios

Sine = Opposite over Hypotenuse (SOH)

Cosine = Adjacent over Hypotenuse (CAH)

Tangent = Opposite over Adjacent (TOA)

Now lets look back at the question

We are given an angle and its adjacent side length (11) and we need to find the hypotenuse

The hypotenuse and adjacent sides corresponds with the trig function cosine so we will use cosine to solve for x

( remember that cosine = adjacent over hypotenuse )

cos(37)=\frac{11}{x}

step 1 multiply each side by x

cos(37)*x=xcos(37)\\\frac{11}{x} *x=11

now we have xcos(37)=11

step 2 divide each side by cos(37)

\frac{xcos(37)}{cos(37)} =x\\\frac{11}{cos(37)} =13.77349\\

we're left with x = 13.77439

Our last step would be to round to the nearest tenth

We would get that the answer is 13.8

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2 years ago
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