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2 years ago

A circle has the equation (x-2)^2+y^2=5. Whay are the coordinates of the circles center?

Mathematics

2 answers:

erica [24]2 years ago

8 0

Answer:

(2,0)

Step-by-step explanation:

Following the circle formula: $(x-h)^2 + (y-k)=r^2$ , we can deduce the values of Point(h,k).

The point is (2,0).

zloy xaker [14]2 years ago

4 0

(x-h)^2 + (y-k)^2 = r^2

(x-2)^2 + (y-0)^2 = (rt(5))^2

-h = -2
h = 2

k=0

Center(2, 0)

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Read 2 more answers

Write an equation in slope intercept form for the given slope. (5,9).(6,8)

vovangra [49]

Answer:

The equation in slope intercept form for (5,9) and (6,8) is y = 3x-10

Solution:

Given that (5,9) and (6,8)

Here, $x_{1}=5 ; y_{1}=5 ; x_{2}=6 ; y_{2}=8$

We know the slope of an equation is given by y = mx+c

To find the value of m, we use the below given formula

$\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting the values we get,

$\mathrm{m}=\frac{8-5}{6-5}$

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Putting the value of m in the slope intercept form we get,

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