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3 years ago

A circle has the equation (x-2)^2+y^2=5. Whay are the coordinates of the circles center?

Mathematics

2 answers:

erica [24]3 years ago

8 0

Answer:

(2,0)

Step-by-step explanation:

Following the circle formula: $(x-h)^2 + (y-k)=r^2$ , we can deduce the values of Point(h,k).

The point is (2,0).

zloy xaker [14]3 years ago

4 0

(x-h)^2 + (y-k)^2 = r^2

(x-2)^2 + (y-0)^2 = (rt(5))^2

-h = -2
h = 2

k=0

Center(2, 0)

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The translation of the given figure will have vertices, A'(1,2), B'(3,2), C'(3,-5), and D(-1,-3) from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

In the question, we are asked to translate the given figure 2 units left and 7 units down.

In the translation, the left-right movement implies the change in the x-coordinate, whereas the up-down movement implies the change in the y-coordinate.

For any point P(x, y) the given rule says that after translation,

P(x, y) becomes P'(x - 2, y - 7).

The coordinates of the given figure are:

A(3,9), B(5,9), C(5,2), and D(1,4).

After translation, these points can be shown as:

A(3,9) becomes A'(1,2).

B(5,9) becomes B'(3,2).

C(5,2) becomes C'(3,-5).

D(1,4) becomes D'(-1,-3).

Thus, the translation of the given figure will have vertices, A'(1,2), B'(3,2), C'(3,-5), and D(-1,-3) from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

Learn more about translations at

brainly.com/question/1400185

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