All categories

4 years ago

When supply is > demand for a business is: a. High profit b. Customer dissatisfaction impact c. Ideal d. Wasteful/Costly

Business

1 answer:

egoroff_w [7]4 years ago

3 0

Answer:

The correct answer is letter "B": Customer dissatisfaction impact.

Explanation:

Customer dissatisfaction arises when the good or service provided by a company does not meet the needs of the consumers. The direct result of this situation is reflected in the quantity demanded of the product in reference, provoking an overload of supply since the buyers start purchasing less every time.

You might be interested in

Mmaglaya1 It says that I have to write at least 20 letters

VLD [36.1K]

hmmm...let me see......oh....free free free....free free....um...free?

hope that helps

5 0

3 years ago

A company is considering replacing an old piece of machinery, which cost $601,300 and has $350,900 of accumulated depreciation t

Kazeer [188]

Answer:

Question Aa. Alternative 1–$1,253,600

Alternative 2 –$1,230,300

Differential effect $ 23,300

b.The company should replace the old machine.

c Sunk cost $250,400

Question Ba. Alternative 1–$488,000

Alternative 2 –$466,000

Differential effect $ 22,000

b.The company should replace the old machine.

c Sunk cost $250,000

Explanation:

Question Aa. Preparation of a differential analysis dated September 13

DIFFERENTIAL ANALYSIS

Continue with Old Machine (Alt. 1) or Replace Old Machine (Alt. 2)

September 13

Continue with Old Machine (Alternative 1); Replace Old Machine (Alternative 2) ; Differential

on Income (Alternative 2)

Revenues:

Proceeds from sale of old

machine $ 0 $64,500 $64,500

Costs:

Purchase price 0 –$483,600 –$483,600

Variable production costs (8 years)–$1,253,600 –$811,200 $442,400

($156,700*8=$1,253,600)

($101,400*8=$811,200)

Income (Loss) –$1,253,600 –$1,230,300 $ 23,300

b. The company should replace the old machine.

c. Calculation for The sunk cost

Using this for formula

Sunk cost= Book value- Accumulated

depreciation

Let plug in the formula

Sunk cost=$601,300-$350,900

Sunk cost=$250,400

Question Ba. Preparation of a differential analysis dated September 13

DIFFERENTIAL ANALYSIS

Continue with Old Machine (Alt. 1) or Replace Old Machine (Alt. 2)

September 13

Continue with Old Machine (Alternative 1); Replace Old Machine (Alternative 2) ; Differential

on Income (Alternative 2)

Revenues:

Proceeds from sale of old

machine $ 0 $231,000 $231,000

Costs:

Purchase price 0 –$545,000 –$545,000

Variable production costs (8 years)–$488,000 –$152,000 $336,000

($61,000*8=$488,000)

($19,000*8=$152,000)

Income (Loss) –$488,000 –$466,000 $ 22,000

b. The company should replace the old machine.

c. Calculation for The sunk cost

Using this for formula

Sunk cost= Book value- Accumulated

depreciation

Let plug in the formua

Sunk cost=$600,000-$350,000

Sunk cost=$250,000

6 0

2 years ago

When interest is compounded continuously, the amount of money increases at a rate proportional to the amount S present at time t

liubo4ka [24]

Answer:

a) - r=5%: $S=$ 5,136.10$

- r=4%: $S=$ 4,885.61$

- r=3%: $S=$ 4,647.34$

b) - r=5%: t=14 years

- r=4%: t=17 years [/tex]

- r=3%: t=23 years [/tex]

c) The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

Explanation:

The rate of accumulation of money is

$dS/dt=rS$

To calculate the amount of money accumulted in a period, we have to rearrange and integrate:

$\int dS/S=\int rdt=r \int dt\\\\ln(S)=C*r*t\\\\S=C*e^{rt}$

When t=0, S=S₀ (the initial capital).

$S=S_0=Ce^{r*0}=Ce^0=C\\\\C=S_0$

Now we have the equation for the capital in function of time:

$S=S_0e^{rt}$

a) For an initial capital of $4000 and for a period of five years, the amount of capital accumulated for this interest rates is:

- r=5%: $S=4000e^{0.05*5}=4000*e^{0.25}= 5,136.10$

- r=4%: $S=4000e^{0.04*5}=4000*e^{0.20}= 4,885.61$

- r=3%: $S=4000e^{0.03*5}=4000*e^{0.15}= 4,647.34$

b) We can express this as

$S=S_0e^{rt}\\\\2S_0=S_0e^{rt}\\\\2=e^{rt}\\\\ln(2)=rt\\\\t=ln(2)/r$

- r=5%: $t=ln(2)/0.05=14$

- r=4%: $t=ln(2)/0.04=17$

- r=3%: $t=ln(2)/0.03= 23$

c) When the interest is compuonded quarterly, the anual period is divided by 4. In 5 years, there are 4*5=20 periods of capitalization. The annual rate r=0.0525 to calculate the interest is also divided by 4:

$S = 4000 (1+(1/4)(0.0525))^{5*4}=4000(1.013125)^{20}\\\\S=4000*1.297958= 5,191.83$

If compuonded continously, we have:

$S=S_0e^{rt}=4000*e^{0.0525*5}=4000*1.3= 5,200.71$

The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

5 0

3 years ago

May i have the answer for this im not quite sure

natali 33 [55]

Answer:

styd7tiho8ts7rt8di8yoy8s8t7rs8s88tdtzt

7 0

3 years ago

Camellia, a merchandising company, has provided the following extracts from their budget for the first quarter of the forthcomi

MrRissso [65]

Answer:

555 000 US$ 

Explanation:

Cash sales(25%) Credit sales(75%) 

January (400,000*25%)=100000 (400,000-100000)=300,000

February (600,000*25%)=150,000 (600,000-150,000)=450,000

Customer collections to the month of February.

= $150,000 + ($450,000 * 0.7) + ($300,000*0.3)

(Balance collections = (100 - 70) = 30%) 

8 0

3 years ago