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serious [3.7K]
4 years ago
14

In Chemistry class, Andrew has earned scores of 64, 69, and 73 on three tests. He must maintain an average of 70 to pass the cou

rse. What score must Andrew earn on the final exam to pass the course?
Mathematics
1 answer:
Nikolay [14]4 years ago
8 0
64+69+73 = 206

\frac{206+x}{4} =70

206+x=280

x=74

Andrew needs at least a 74% on the final exam.

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If a 32 ft rope is cut into two sections with one section 7 times as log as the other section, how long is teh shorter piece?
steposvetlana [31]
The total length of the rope = 32 ft
It is cut into two sections, say x and y
But one section is seven times the other, say y=7x (shorter section being x)
Solving for x

x+y =32
x+7x = 32
8x=32
x=32/8 = 4 ft.
Therefore, the shorter piece is 4 ft long.
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Consider the following equation.
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Answer:

7/3

Step-by-step explanation:

because (x,y) is the coordinates , 3/2 is y

y = 3/2

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x * 4 * 3/2 = 14

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A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000
Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

p_1=X_1/n_1=494/1000=0.494

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

p_2=X_2/n_2=552/1000=0.552

The difference between proportions is (p1-p2)=-0.058.

p_d=p_1-p_2=0.494-0.552=-0.058

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022

Then, the margin of error is:

MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

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