Total weight, w = 10 lbs.
Height of the bucket, h = 2 feet.
Distance walked, d = 100 ft.
Now, work done in moving the bucket at a height of 2 feet.
W = mgh
W = 2× 32.17×100
W = 6434 lbs ft²/s²
Work done in moving bucket in horizontal direction is zero because it is perpendicular to the force.
Therefore, work done is 6434 lbs ft²/s² .
Hence, this is the required solution.
Answer:
5 and 2/10
Step-by-step explanation:
You have to have a common denominator
11/9
To find the slope
m = ( y2-y1)/(x2-x1)
= ( 9 - -2)/(1 - -8)
= ( 9+2)/ (1+8)
= 11/9
a) 4, b) 10
a)
1) - 7 + 3 = - 4
2) | - 4| = 4
b)
1) |- 7| = 7
2) 7+3 = 10
the answer is c
I hope this helps
