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Mariulka [41]
4 years ago
11

What is the maximum number of intersection points between a quadrilateral and a triangle?

Mathematics
2 answers:
disa [49]4 years ago
8 0

→A Quadrilateral is four sided Polygon.

→And ,A Triangle is three sided polygon.

⇒Take any kind of Quadrilateral(Parallelogram,Square,Rectangle,Rhombus,Trapezoid,Kite), and any type of Triangle (Scalene, Isosceles,or Equilateral,Right,Obtuse,Acute),there can be Maximum of six Intersection point between a quadrilateral and a triangle.

ELEN [110]4 years ago
7 0
A quadrilateral is a four sided figure but it does not have to be a rectangle, square or parallelogram. Instead it can be a v-shaped concave figure and still have four sides. Therefore, with this  quadrilateral a triangle can intersect with it 8 times.
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5 0
3 years ago
In a 10 mile race, Janet covered the first 2 miles at a constant rate. She then sped up and rode her bike the last 8 miles at a
xenn [34]

Answer:

0.83\text{ miles per minute}

Step-by-step explanation:

GIVEN: In a 10 mile race, Janet covered the first 2 miles at a constant rate. She then speed up and rode her bike the last 8 miles at a rate that was 0.5 miles per minute faster. Janet's overall time would have been 2 minutes faster had she ridden her bike the whole race at the faster pace.

TO FIND: What was Janet's average speed (in miles per minute) for the whole race?

SOLUTION:

let the speed of Janet in first 2\text{ miles}  =x\text{ miles per minute}

speed of Janet's bike in last 8\text{ miles}  =x\text{+0.5 miles per minute}

total time taken by Janet,

\text{Time}=\frac{\text{distance}}{\text{speed}}

\text{Time taken}=\frac{2}{x}+\frac{8}{x+0.5}\text{minute}

Time taken if Janet rides whole race at faster pace =\frac{10}{x+0.5}\text{minute}

 

As, Janet's overall time would have been 2\text{ minutes} faster had she ridden her bike the whole race at the faster pace.

\frac{2}{x}+\frac{8}{x+0.5}=\frac{10}{x+0.5}+2

\frac{2}{x}-\frac{2}{x+0.5}=2

\frac{1}{x}-\frac{1}{x+0.5}=1

x^{2} +0.5x-1=0

on solving we get

x=0.5\text{ miles per minute}

\text{Time taken}=\frac{2}{x}+\frac{8}{x+0.5}\text{minute}

\text{Time taken}=\frac{2}{0.5}+\frac{8}{1}\text{minute}

\text{Time taken}=\frac{2}{x}+\frac{8}{x+0.5}\text{minute}

\text{Time taken}=12\text{minute}

Average speed =\frac{\text{total distance}}{\text{time taken}}

Average speed =\frac{10}{12}=0.83\text{miles per minute}

Therefore average speed of Janet was 0.83\text{ miles per minute}

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3 years ago
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Answer:

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Step-by-step explanation:

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