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3 years ago

What is the maximum number of intersection points between a quadrilateral and a triangle?

Mathematics

2 answers:

disa [49]3 years ago

8 0

→A Quadrilateral is four sided Polygon.

→And ,A Triangle is three sided polygon.

⇒Take any kind of Quadrilateral(Parallelogram,Square,Rectangle,Rhombus,Trapezoid,Kite), and any type of Triangle (Scalene, Isosceles,or Equilateral,Right,Obtuse,Acute),there can be Maximum of six Intersection point between a quadrilateral and a triangle.

ELEN [110]3 years ago

7 0

A quadrilateral is a four sided figure but it does not have to be a rectangle, square or parallelogram. Instead it can be a v-shaped concave figure and still have four sides. Therefore, with this quadrilateral a triangle can intersect with it 8 times.

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How many times does 0.6 go into 12.66?<br> first brainlyist

aleksklad [387]

Answer:

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8 0

3 years ago

Connor rolled a die 6 times. A 2 occurred three times. Why isn't the theoretical probability 3/6 instead of 1/6?

Cerrena [4.2K]

2 occurred 3times

$\\ \sf\longmapsto S=6\times 3=18$

$\\ \sf\longmapsto |S|=18$

Now

$\\ \sf\longmapsto E=No\:of\:times\: 2\:occured$

$\\ \sf\longmapsto |E|=3$

we know

$\boxed{\sf P(E)=\dfrac{|E|}{|S|}}$

$\\ \sf\longmapsto P(E)=\dfrac{3}{18}$

$\\ \sf\longmapsto P(E)=\dfrac{1}{6}$

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3 years ago

What is the final price for a pair of $39.50 jeans after 5% sales tax has been added?

makkiz [27]

The answer will be $41.45 or $41.46 i'm not sure what you answer choices are! hope this helped!

7 0

4 years ago

Read 2 more answers

The dimensions of a rectangle box are consecutive integers. If the box has volume of 13,800 cubic centimeters, what are its dime

klasskru [66]

Three consecutive integers are x, x+1, x+2.
The volume of a rectangular box is the product of its three dimensions. The volume is 138000 cm³.

$x(x+1)(x+2)=13800 \\
(x^2+x)(x+2)=13800 \\
x^3+2x^2+x^2+2x=13800 \\
x^3+3x^2+2x-13800=0 \\
x^3-23x^2+26x^2-598x+600x-13800=0 \\
x^2(x-23)+26x(x-23)+600(x-23)=0 \\
(x^2+26x+600)(x-23)=0 \\ 
x^2+26x+600=0 \ \lor \ x-23=0 \\ \\
1. \\
x^2+26x+600=0 \\ \\
a=1 \\ b=26 \\ c=600 \\ \Delta=b^2-4ac=26^2-4 \times 1 \times 600=676-2400=-1724 \\
\hbox{the discriminant is less than 0 so there are no real solutions} \\ \\
2. \\
x-23=0 \\
x=23 \\ \\
x+1=23+1 =24 \\ \\
x+2=23+2=25$

The dimensions of the box are 23 cm x 24 cm x 25 cm.

5 0

3 years ago

The principal randomly selected six students to take an aptitude test. their scores were: 81.4 78.6 71.3 77.8 76.9 77.7 determin

Firdavs [7]

The confidence interval is $77.28\pm 2.23$ .

We first find the mean. Add together all of the data points and divide by 6, the number of data points; the mean is 77.28.

Next we find the standard deviation. Find the difference between each data point and the mean; square it; find the sum; divide by the number of data points; take the square root. The standard deviation is 3.32.

To find the margin of error, we calculate the z-score associated with this level of confidence. 100-90 = 10% = 0.1; 0.1/2 = 0.05; 1-0.05 = 0.95. Using a z-table (http://www.z-table.com) we see that this is between two scores, 1.64 and 1.65; we will use 1.645.

The margin of error is given by
z * (σ/√n) = 1.645*(3.32/√6) = 2.23.

Thus the confidence interval is 77.28 +/ 2.23.

3 0

3 years ago