The area of a parallelogram is the product of the length of the base and the height measured perpendicular to the base.
1i) (20 cm)*(12 cm) = 240 cm^2
2ii) (7 cm)*(7.5 cm) = 52.5 cm^2
3iii) 27 cm^2 = (6 cm)*h
.. h = (27 cm^2)/(6 cm) = 4.5 cm
Answer:

Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
- Parallel lines will always have the same slope but different y-intercepts.
<u>1) Determine the slope of the parallel line</u>
Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

Switch the sides

Divide both sides by 2 to isolate y

Now that this equation is in slope-intercept form, we can easily identify that
is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope
. Plug this into
:

<u>2) Determine the y-intercept</u>

Plug in the given point, (4,0)

Subtract both sides by 6

Therefore, -6 is the y-intercept of the line. Plug this into
as b:

I hope this helps!
Given:
The figure.
To find:
The segment bisector of MN and value of MN.
Solution:
From the given figure it is clear that ray RP,i.e.,
is the segment bisector of MN because it divides segment MN in two equal parts.
Now,


Since,
is the segment bisector of MN, therefore,



Therefore, the length of MN is
.
C)
Area of full triangle
1/2(8)(6)=24cm^2
Area of non shaded triangle
1/2(4)(3)=6cm^2
Area of full minus area of small triangle
24-6=18cm^2
D)
Area of Big rectangle
(4)(12)=48
Area of non shaded triangle
1/2(9)(4)=18
Area of Big rectangle minus non shaded triangle
48-18=30cm^2