Answer:
i). x³ + 9x² + yz - 15
ii). -21m³np - 8p⁵q + mnp + 4mn + 100
Step-by-step explanation:
Question (38)
i). Two expressions are -5x² - 4yz + 15 and x³+ 4x²- 3yz
By subtracting expression (1) from expression (2) we can the expression by addition which we can get expression (1).
(x³+ 4x²- 3yz) - (-5x² - 4yz + 15) = x³ + 4x² - 3yz + 5x² + 4yz - 15
= x³ + 9x² + yz - 15
ii). -15m³np + 2p⁵q - 6m³pn + mnp + 4mn - 10qp⁵+ 100
= (-15m³np - 6m³np) + (2p⁵q - 10qp⁵) + mnp + 4mn + 100
= -21m³np - 8p⁵q + mnp + 4mn + 100
Girl ain’t no way you can’t figure this out? the labeling is easy but like just look up the functions
Remember
area=pir^2
circumference=2pir
the surface aera if you thinkg about it is
2 times the tops+area around
the tops are circles so 2*pir^2 is tops
the area around is a rectangle that has been wrapped around the cylinder,
the hieght is the legnth and the circumference is width
so 2hpir is the area around
2pir^2 is the areas of the tops
2hpir is the area around
Answer:
-3.872983346
Step-by-step explanation:
In this case we have: cos θ = 1/4 Whose possible solutions are: θ = 2 * pi * n - Acos (1/4) θ = 2 * pi * n + Acos (1/4) Where, n belongs to the natural numbers. As sin θ <0 then the solution is: θ = 2 * pi * n - Acos (1/4) For n = 1 we get: θ = 4.965069236 radians Thus: tan θ = tan (4.965069236) = - 3.872983346 Answer: tan θ = -3.872983346
