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3 years ago

Can someone help me? -Geometry

Mathematics

2 answers:

alexgriva [62]3 years ago

4 0

The answer is (3.14)(6^2)(9).

nlexa [21]3 years ago

4 0

Answer:

1/3(3.14)(6^2)(9)

Step-by-step explanation:

V = 1/3 · (π · r · 2) · ( h )

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Simplify (-4x^2-3y-8)+(5y-2x^2+1)

ddd [48]

Add the like terms.

The like terms in this case are:

-4x^2 and -2x^2

This makes -6x^2

-3y and 5y

This makes 2y

-8 and 1

This makes -7

Your answer is (-6x^2+2y-7)

8 0

3 years ago

Each month, Miss Patrick spends $60 on transportation to work, and earns $24.50 per hour.Each month, Mr. Shah spends $150 on lab

Semmy [17]

Answer:

3 hours for miss patrick 5 hours for mr shah

Step-by-step explanation:

5 0

3 years ago

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What is the best approximation for the input value when f(x)=g(x)?

Lostsunrise [7]

Answer:

$x=0$ and $x=1$ .

Step-by-step explanation:

If we have to different functions like the ones attached, one is a parabolic function and the other is a radical function. To know where $f(x)=g(x)$ , we just have to equalize them and find the solution for that equation:

$x^{2}=\sqrt{x} \\(x^{2} )^{2}=(\sqrt{x} )^{2}\\x^{4}=x\\x^{4}-x=0\\x(x^{3}-1)=0\\$

So, applying the zero product property, we have:

$x=0\\x^{3}-1=0\\x^{3}=1\\x=\sqrt[3]{1}=1$

Therefore, these two solutions mean that there are two points where both functions are equal, that is, when $x=0$ and $x=1$ .

So, the input values are $x=0$ and $x=1$ .

8 0

3 years ago

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An athlete runs around a circular track. The track has a diameter of 200 feet. How many laps does she need to take to run a mile

Shtirlitz [24]

First you have to figure out the length of the track:

$2 * \pi * r$

r is the half of the diameter:
200ft : 2 = 100ft

$2* \pi *100ft$ = 200 $\pi$ ≈ 628,31

The athlete has to run ca. 5280ft for one mile:

5280 : 628,31≈8,4

The athlete has to run 8,4 laps

3 0

3 years ago

How many different phone numbers are possible in the area code 503, if the first number cannot start with a 0 or 1

ElenaW [278]

Answer:

8 X 10^(9)

Step-by-step explanation:

Originally we have 10 digit phone numbers excluding the area code.

For each face value we have these in store: 0,1,2,3,4,5,6,7,8,9 (total 10)

But if we exclude 1 and 0 for the first digit, we are left with 8 digits.

8P1 X .......

In a phone number, digits can repeat so we can choose out of these 10 numbers freely after this.

8P1 X 10P1 X 10P1 X...

Adding the area code while assuming 10P1 is just 10...we get:

1 X 1 X 1 X 8 X 10^(9)

= 8000000000

Very interesting question, thanks for the opportunity!

7 0

3 years ago

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