Answer:
The advertisement should use 16 minutes.
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:

In which
is the decay parameter.
The probability that x is lower or equal to a is given by:

Which has the following solution:

The probability of finding a value higher than x is:

The manager of a fast-food restaurant determines that the average time that her customers wait for service is 3.5 minutes.
This means that 
What number of minutes should the advertisement use?
The values of x for which:

So






Rounding to the nearest number, the advertisement should use 16 minutes.
Yolanda had 47 customers on Saturday from 6 to 7 pm. Then on Monday she only had 20 customers from 5pm to 6pm.
Question: Let’s find how much percentage rate did Yolanda’s customer’s decreased over time.
Solution
=> Saturday = 47 customers.
=> Monday = 20 customer.
Let’s start solcing
=> 47 – 20 = 27
There are 27 customer that were lost over time.
=> 27 / 47 = 0.57 * 100 = 57%
Let’s try checking our answer:
=> 47 * .57 = 26.79 or round off to 27, since we rounded off also our percentage.
Answer:9
Step-by-step explanation:
dk
Answer:
C. (2, 5)
Step-by-step explanation:
Looking at the answer choices, you can see that solving for y will tell you which choice is correct. We can eliminate x from the equations by adding 4 times the second equation to the first:
(8x -3y) +4(-2x +3y) = (1) +4(11) . . . . . adding the equations to eliminate x
9y = 45 . . . simplified; next we divide by 9
y = 5 . . . . . matches choice C
_____
Check
8(2) -3(5) = 16 -15 = 1
-2(2) +3(5) = -4 +15 = 11 . . . . the answer checks OK in both equations