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makkiz [27]
3 years ago
14

9.2 HW Central Angles, Arc Measures, & Arc Length

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

here i hope this help im not sure if a can find the exact answer your looking for but here is a formula

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Please solve it help me ..............<br>​
Sedbober [7]

Answer:

(a) = iv

b = i

c= ii

d = iii

Q-3

- radical 3

Step-by-step explanation:

8 0
2 years ago
S’tone anyone know this by chance ?!!!
kenny6666 [7]

Answer: 3

Step-by-step explanation:

8 0
3 years ago
Which graph represents the function f (x) = StartFraction 2 Over x minus 1 EndFraction + 4?
Pepsi [2]

Answer:

On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4

Step-by-step explanation:

The given function is presented as follows;

f(x) = \dfrac{2}{x - 1} + 4

From the given function, we have;

When x = 1, the denominator of the fraction, \dfrac{2}{x - 1}, which is (x - 1) = 0, and the function becomes, \dfrac{2}{1 - 1} + 4 = \dfrac{2}{0} + 4 = \infty + 4 = \infty therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote

Also we have that in the given function, as <em>x</em> increases, the fraction \dfrac{2}{x - 1} tends to 0, therefore as x increases, we have;

\lim_  {x \to \infty}  \dfrac{2}{(x - 1)} \to 0, and \  \dfrac{2}{(x - 1)}  + 4 \to 4

Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1

When -∞ < x < 1, we also have that as <em>x</em> becomes more negative, f(x) → 4. When x = 0, \dfrac{2}{0 - 1} + 4 = 2. When <em>x</em> approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left

Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.

5 0
3 years ago
Find the length of the radius for this circle.
pychu [463]
We know that the 8 represent the squared radius of the circle so to get the radius we should take the square root of 8 
the answer is √8 = 2√2
7 0
3 years ago
Read 2 more answers
BRAINLIEST PLS HELP <br><br> Solve for x:<br><br><br><br> x = 10<br> x = 30<br> x = 0<br> x = 1
Vedmedyk [2.9K]

Answer:

x=0

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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