All categories

4 years ago

Which number is an integer? -3/4 0 2.3 pi

Mathematics

2 answers:

mixer [17]4 years ago

8 0

Answer:

0 is an integer.

Step-by-step explanation:

An integer is a whole number ( and is not a fraction) which could be positive as well as negative or zero. integer comes in the category of Rational numbers i.e. they are contained in Rational numbers.

The set of integers are:

{...............-3, -2 , -1 , 0, 1 ,2 ,3,..........}

Hence the answer is:

0 is an integer.

( whereas -3/4 and 2.3 which could also be written as 23/10 are rational numbers but are not integers.

and pi (π ) is an irrational number )

Daniel [21]4 years ago

4 0

The answer is 0, since integers are whole numbers.

You might be interested in

The function f is such that f(x)=4x-1 find f^-1(x)

zvonat [6]

Let y=4x-1
The inverse is basically expressing x in terms of y.
y=4x-1 =>
y+1=4x
x=(y+1)/4
Since the inverse is still a function of x, we only have to interchange x and y
inverse of f(x) = f^-1(x) = (x+1)/4

4 0

3 years ago

I'll give brainliest this is due soon so yeahmPLSSSSSSSSS

lora16 [44]

Answer:

He pays taxes on the amount after the discount. So 10% of $40.50 versus $45.

Step-by-step explanation:

10% on $40.50 = $4.05

10% on $45.00 = $4.50

4 0

3 years ago

Read 2 more answers

A.The value of a book is $340 and

Oksanka [162]

Answer:

a. $190.3

b. $3.94

5 0

4 years ago

Is 2/5 greater then 0.5?

ExtremeBDS [4]

The answer is No.
The reason being is that in $\frac{2}{5}$ , if you divide 2 by 5, it is .4
Which is less than .5
$\frac{2}{5}$ <.5

7 0

3 years ago

Read 2 more answers

Choose the best description of the roots of the equation 3x 2 - 4x + 5 = 0.

Naily [24]

For this case we have the following polynomial:
$3x ^ 2 - 4x + 5 = 0
$
Using the resolver we have:
$x = \frac{-b +/- \sqrt{b^2 - 4ac}}{2a}$
Substituting values we have:
$x = \frac{-(-4) +/- \sqrt{(-4)^2 - 4*3*5}}{2*3} 

$
$x = \frac{4 +/- \sqrt{16 - 60}}{6}$
$x = \frac{4 +/- \sqrt{-44}}{6}$
$x = \frac{4 +/- \sqrt{-4*11}}{6}$
$x = \frac{4 +/- 2\sqrt{-11}}{6}$
$x = \frac{2 +/- \sqrt{-11}}{3}$
$x = \frac{2 +/- i\sqrt{11}}{3}$
Answer:
We observe that the solution to the quadratic equation are two imaginary roots.

7 0

3 years ago