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castortr0y [4]
4 years ago
5

Using special products what is (wx-y)^2

Mathematics
1 answer:
VikaD [51]4 years ago
4 0
I think that supposed to be (wx - y^2)^2?

If so, multiply using FOIL:

First: wx * wx = w^2x^2

Outside: wx * -y^2 = -wxy^2

Inside: -y * wx = -wxy^2

Last: -y^2 * -y^2 = y^4

Combine w^2x^2 - 2wxy^2 + y^4
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eugene wants to buy jeans at a store that is giving $10 off everything. the tav on the jeans is marked 50% off. the original pri
Kipish [7]
<span>Eugene wants to buy jeans at a store that is giving $10 off everything.
Now, the tav on the jeans is marked 50% off and the original price is $49.98.
Let’s find the total cost if the 50% discount is applied before the $10 discount
Solutions:
=> 49.98 dollars * .50 = 24.99
Subtract this to get the answer:
=> 49.98 – 24.99 = 24.99 dollars, this is now that price of the jeans before 10 dollars discount is applied.</span>



4 0
3 years ago
Read 2 more answers
What’s the product and the units
antoniya [11.8K]

Answer:

114 mi

Step-by-step explanation:

6h*\frac{19 mi}{h}=\frac{6h*19mi}{h} \frac{6*19mi}{1} =114mi

7 0
3 years ago
Would someone plz tell me what these are
AVprozaik [17]

Answer:

The little lines mean the sides are the same. Like length.

8 0
3 years ago
C=0.04x^2-8.504x+25302 how do i do this?
erma4kov [3.2K]
Solving for x.

Since x<span> is on the right-hand side of the </span>equation<span>, switch the sides so it is on the left-hand side of the </span>equation<span>.
</span><span>0.04<span>x2</span>−8.504x+25302=c

</span>Simplify the quadratic and set<span> the right side equal to </span><span>0.
</span><span>0.04<span>x2</span>−8.504x+25302−c=0

</span>Use the standard form of the quadratic <span>(<span><span>a<span>x2</span>+bx+c</span>)</span></span><span> to find </span><span>a,</span><span>b,</span><span> and </span>c<span> for this quadratic.
</span><span>a=0.04,</span><span>b=−8.504,</span><span>c=25302−1c

</span>Use the quadratic formula<span> to find the </span>solutions<span>.
</span><span>x=<span>−b ± </span></span>√<span><span> <span><span>b2</span>−4ac /</span> </span><span>2a

</span></span>Substitute in the values of <span><span>a=0.04</span>,</span><span><span>b=−8.504</span>,</span><span> and </span><span><span>c=25302−1c</span>.
</span>x=<span>−(−8.504) ±</span>√<span><span>(−8.504<span>)2</span>−4(0.04)(25302−1c)/</span><span>2(0.04)
</span></span>
<span>Simplify.
</span>x=<span>8.504 ±</span>√<span><span>(−8.504<span>)2</span>−4(0.04)(25302−1c)/</span><span>2(0.04)
</span></span>
Simplify the section inside the radical<span>.
</span>x=<span>8.504 ± </span>√<span><span><span>−3976.001984+0.16c</span>/</span><span>2(0.04)
</span></span>
Simplify the denominator<span> of the </span>quadratic formula<span>.
</span>x=<span>8.504 ±</span>√<span><span>−3976.001984+0.16c/</span>0.08
</span>

Answer:
x=8.504 ±√−3976.001984+0.16c/0.08


6 0
3 years ago
What are the steps for using a compass and straightedge to construct a regular hexagon inscribed in a circle?
N76 [4]
The steps to construct a regular hexagon inscribed in a circle using a compass and straightedge are given as follows:

1. <span>Construct a circle with its center at point H.

2. </span><span>Construct horizontal line l and point H on line l

3. </span>Label the point of intersection of the circle and line l to the left of point H, point J, and label the point of intersection of the circle and line l to the right of point H, point K.<span>

4. Construct a circle with its center at point J and having radius ​ HJ ​ . Construct a circle with its center at point K having radius ​ HJ

5. </span><span>Label the point of intersection of circles H and J that lies above line l, point M, and the point of their intersection that lies below line l, point N. Label the point of intersection of circles H and K that lies above line l, point O, and the point of their intersection that lies below line l, point P.

6. </span><span>Construct and JM⎯⎯⎯⎯⎯, MO⎯⎯⎯⎯⎯⎯⎯, OK⎯⎯⎯⎯⎯⎯⎯, KP⎯⎯⎯⎯⎯, PN⎯⎯⎯⎯⎯⎯, and NJ⎯⎯⎯⎯⎯ to complete regular hexagon JMOKPN .</span>
3 0
3 years ago
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