Answer:
a) 0.80
b) 0.72
c) 0.02
Step-by-step explanation:
It is assumed that
X = Bit transmitted
Y = Bit received
= Transmissted bit is 0
= Transmissted bit is 1
= Received bit is 0
= Received bit is 1
As per the given condition
P [ | ] = 90%
P [ | ] = 100% - 90% = 10%
P [ | ] = 74%
P [ | ] = 100% - 74% = 26%
P [ Tramitted bits are 0 ] = 80%
Now calculate each situation
a)
As all the transmitted bits are o has possibilit of 80% then
P [ X = 0 ] = P [ ] = 80% = 0.80
b)
P [ X = 0, Y = 0 ] = P [ , ] = P [ | ] x P [ ] = 90% x 80% = 72% = 0.72
c)
P [ X = 1, Y = 0 ] = P [ , ] = P [ | ] x P [ ] = 10% x ( 100% - 80% ) = 10% x 20% = 2% = 0.02
A is the correct answer. 23/40=0.575 and 4.6/8= 0.575 as well.
Answer:
<em>10</em>
Step-by-step explanation:
<em>To solve this, we have to do 4 divided by 2/5, because there are stops every 2/5 mile of a 4-mile track.</em>
<em>To make dividing easier, you can write 4 as a fraction, which would be 4/1</em>
<em>Now, divide:</em>
<em>4/1 ÷ 2/5</em>
<em>Remember that when you divide a fraction by another fraction, you can multiply the first fraction by the reciprocal of the second fraction and get the same fraction.</em>
<em>The reciprocal of 2/5 is 5/2.</em>
<em>So 4/1 x 5/2 = 20/2, which can be simplified as 10.</em>
<em>So there are 10 stops. </em>^-^
The formula for f(x) in y + 6 = 5(x - 4) in terms of x is f(x) = 5(x - 4) - 6